Page 142 - Analog and Digital Filter Design
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                                                              Analog Lowpass Filters






















                 Figure 4.14
                 Frequency Scaling of Pole
                 Location in S-Plane

                       Each pole has a certain natural frequency (m,,) and a certain magnifying factor
                       (Q). The Q depends on the angle of  the line from the S-plane origin to the pole
                       location.  As the pole-zero  diagram is scaled for a higher cutoff  frequency. the
                       pole  moves along  the  line  from  the  S-plane origin  to  the  pole  location.  This
                       means that  the value of  Q remains unchanged as the pole location is scaled for
                       frequency. The natural frequency w,, is dependent upon the "o" coordinate (real
                       part), and this changes in proportion to the scaling of  the diagram. More detail
                       of  frequency scaling of poles is given in the Appendix.

                       Zeroes are located on the imaginary axis. so scaling is simple. They are moved
                       along this axis in proportion  to the scaling frequency.

                       Choose a capacitor value and then use the equations given here to find the re-
                       sistor  values.  If  the  resistor  values  are  very  small  or very  large.  select  a  new
                       capacitor  value and try again. Again.  aim to keep the resistor  values between
                       1 kR and  100 kR. Here is an example for a biquad filter.
                       For  example,  design  a  second-order  biquad  filter,  based  on  an  Inverse
                       Chebyshev design. The filter should have a passband of  1 kHz and a 30dB stop-
                       band attenuation. Using the pole and zero location in Tables 3.17 and 3.18 given
                       in Chapter 3, for a  3dB passband  attenuation  at  1 rad/s.  the zero is at 5.71025
                       and the poles are at 0.70658 f j0.72929.

                       To scale these for a  1 kHz passband, multiply the pole and zero locations by  the
                       frequency scaling factor 2 nFc = 6283 radls. Hence FL = 35.877.5 radls. The scaled
                       poles  are located  at 4439.44 f j4582.13  (CT = 4439.44  and  w = 4582.13). The
                       natural  frequency of  this pair of  poles is given by
                             w,, = do' +w'  = 6380 rad/s.
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