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(KT Iq) =  v,- =  0.026 volt direct current (DC) at room temperature. V is also  known
                                                                                            T
            as the thermal voltage.
            The  small  signal  transconductance  of the  bipolar  transistor  at  a  particular  DC
            collector current  ICQ  is given  by



                  mall  i  11  1 = _ "_,  =   I  'Q                                 ---                 13-2)
                                               "'  = ________ -
                                   I  ' f\
                                    ''I'   0.026 V                                              m
                                   --er-
            If we did  not know about Equation  (13-2),  there is  another way to indirectly come
            up  with  the transistor's transconductance  by  plugging  values  into Equation  (13-1).
            For Table 13-1, Is = 0.01  pA.  Note that the transconductance is independent of the
            value of Is.
            TABLE  13-1 Calculated Small Signal Transconductances of a Bipolar Transistor




                                                                       ~IC                      lea
                                                                      --
                      VBE                       le                    ~VBE                   0.026 V

                    0.59867                0.1000 mA
                    0.59967                0.1039  mA           0.0039  mAil mV           0.00384 mAl
                                                                                         1 mV  @  0.1  mA

                    0.65854                1.0000 mA
                    0.65954                1.0392 mA            0.0392  mAil mV            0.0384 mAl
                                                                                         1 mV@ 1.0 mA
            From this table,  one can see that Equation  (13-2)  is valid  and  that the small-signal
            transconductance  is  linearly  proportional  to the  DC  coUector  current.  And,  as  seen
            from  Equation  (13-2),  it is valid for calculating  the small-signal transconductance of
            a bipolar transistor. And  by small  signal, we are limiting the alternating-current (AC)

            signa~1  into the base emitter of the transistor to about 5 mV to 15  mV peak to peak.
            If the base-emitter AC signal  is larger than  15  mV peak to peak, gross distortion will
            occur at the output of the collector, and  a large-signal transconductance model will
            have  to be  used.  For example,  Figure  13-6 shows an  input signal  at the  base  and

            emitter of a transistor of about 5 mV  peak  (10  mV  peak to peak)  and  39  mV  peak
            (78  mV  peak  to  peak).  As  can  be  seen  in  the  figure,  for  small  input signals,  the
            collector  current  output  looks  pretty  much  like  a  sine  wave,  but  for  large  input
            signa: ls,  the collector current is larger in amplitude but highly distorted.
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