Page 447 - Cam Design Handbook
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THB13  9/19/03  7:56 PM  Page 435

                                CAM SYSTEM DYNAMICS—RESPONSE               435

               Its primary shortcomings are:
            1. High accuracy is needed to realize the advantage of the mathematically computed curve.
              Sometimes the cam calculated is impossible to cut; i.e. a “dip” in the cam is required.
            2. The mathematical work is laborious and time-consuming.
            3. The cam-follower system is valid at only one speed.



            13.7.2 Fundamental Relationships
            In the following sections a typical example indicating the method of attack establishes the
            basic equations for a high-speed cam-follower system.
               First, the flexibility relationship of the linkage must be determined. Any cam-driven
            mechanism (assuming a single degree of freedom) may be divided into the usual dynamic
            equivalent system of four parts.
            1. Compression  spring—to  hold  the  follower  on  the  cam.  In  positive-drive  cams,  this
              spring obviously does not exist.
            2. An equivalent mass at the end of the follower.
            3. A spring representing the combined elasticity of the linkage.
            4. A cam—The cam and follower motions may be considered the same at speeds low
              enough  that  the  highest  frequency  of  significant  cam  input  is  low  compared  to  the
              system’s natural frequency.
               Since damping and friction are small, they will be neglected. This will greatly simplify
            the mathematical relations. Let
            k s = spring rate of compression spring, lb/in
            k f = spring rate of follower linkage, lb/in
                w
                                                   2
            m =  = equivalent mass at the follower end, lb-sec /in
                g
            w = equivalent weight at follower end, lb
            L = external load acting on follower, lb
            S 1 = initial compression spring force with mass m at zero position, lb
            N = cam speed, rpm
            y = actual lift at follower end, in
            y c = rise of cam, in. (This is not the same as y because of the linkage deflection.)
            q = cam angle of rotation at cam lift y c and follower lift, y, deg
               Mass m (Fig. 13.19) is subjected to an acceleration such that at any instant
                                                 dy
                                                  2
                                      Â  Forces =m  .                    (13.78)
                                                 dt  2
            The forces are
                                  Main spring force =-ky
                                                   s
                                    Linkage force =- (  - )
                                                  ky y
                                                   f    c
                                     External load =-L
                                 Initial spring force =-S
                                                   1
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