Page 105 - Chemical Process Equipment - Selection and Design
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5.3.  MECHANICAL  CONVEYORS  AND  ELEVATORS  77



                EXAMPLE 5.2                                           = [(45.4),/64.4][5.9  + (4.5/D)](4.91D2)
                Size and Power Requirement of a Pneumatic Transfer Line   = 157.1D2(5.9 + 4.5/D)
             A pneumatic firansfer line has 300 ft of  straight pipe, two long radius
             elbows, and  a lift of  50ft. A  two-stage cyclone is  at the receiving   For the solid, take the coefficient of  sliding friction to be f, = 1.
             end.  Solid with a density of  125 Ib/cuft lis  at the rate  of  10 tons/hr   Power  loss  is  made  up  of  four  contributions.  Assume  no  slip
             and  the  free  air  is  at  5000ft/min.  Inlet  condition  is  27psia  and   velocity;
             100°F. Investigate  the  relation  btween  line  diameter  and  power
             requirement.                                           w, = w, + w, + w4+ w,
                On a first pass, the effect of  pressure loss on the density of  the
             air will be neglected.                                   = [u2/2g + A2 +f,L + 2(Q.0488)f,u2]mj
                Mass flow rate of  solid:                             = 5.56[45.4'/64.4  + 50 + 300 + 2(0.0488)45.42]
                                                                      = 3242.5ft lbf/sec.
                rnd  = 20,0800/3600 = 5.56 lb/sec.
                                                                    Total friction power:
                Mass flow rate of  air:
                                                                    wf = 3242.5 + 157.1D2(5.9 + 4.5/D).
                    50061 n
                m;=---   (0.075)D2  = 4.91D2 lb/sec.
                     60  4                                          Pressure drop:
                Density of  air:
                       (3
                p,  = 0.075   ~   = 0.138 lb/cuft.                  Fan power at q = 0.5:

                Density of  mixture:                                .    WC+Y  2e!!.f~~p/tp~,
                                                                    P= 550(0.5)(10) - 2750
                                                                             5000( x/4) D2
                                                                    saturation =   20,000/60   = 11.780, SCFM/(lb/min).
                  -    (rn; + 5.56)
                  -
                    rn:/0.138  + 5.56/125
                                                                         IPS   ~(ft)  rn;   pm   w,   w,
                Linear velocity of  air at inlet:                         3  0.2557 0.3210  2.4808  6362  3484
                                                                          4  0.3356 0.5530  1.5087  10,959  3584
                                                                          5  0.4206 0.8686  1.0142  17,214  3704
                                                                          6  0.5054 1.2542  0.7461  24,855  3837
                                                                                 AP              SCFIVI/
                Assume  air  and  solid  velocities  equal.  Elbow  radius = 120.   1 PS   (psi)   HP/TPH   Ib/min
             Elbow equivalent length,                                       3   10.2     3.58     0.77
                                                                            4    6.1     5.29      I .33
                Le  = 1.6(n/2)(12D) = 30.20                                 5    4.1     7.60      2.08
                                                                            6    2.9    70.44     3.55
             Power for compression from 14.7 psia and 560 R to 27 psia,
                                                                    From Table 5.1, data for pebble Iime are
                k/(k - 1) = 3.5,
                w, = 3.5RT1[(P,/P,)O 2857 - 111.:                     sat = 1.7 SCFM/(lb/min)
                  = 3.5(53.3)(560)[(27/14.7)0.a57 - 1]4.91D2        power = 3.0 HP/TPH
                  = 973050, ft Ib€/sec.                          and for soda ash:
                                                                      sat = 1.9 SCFM/(lb/min)
                Frictional! contribution of  air
                                                                    power = 3.4 HP/TPH.
                    uL                                           The  calculated values  for  a  4in.  line  are  closest  to  the  recom-
                w - - + (O.O15/D)(300 + 2(30.2:1D]rnA
                      ['i
                 1-2g                                            mendations of  the table.



             services. A  related  design is the  apron conveyor with overlapping   For bulk materials, belts are troughed at angles of  20-45".  Loading
             pans of  various shapes and sizes (Fig. 5.8), used primarily for short   of  a  belt  may  be  accomplished  by  shovelling  or  directly  from
             travel  at elevated temperatures.  With  pivoted deep pans they  are   overhead storage or  by  one of  the methods shown on Figure 5.9.
             also effective elevators.                           Discharge is by throwing over the end of  the run or at intermediate
                Flat belts are used chiefly for moving large objects and cartons.   points with plows.
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