Page 130 - Chemical Process Equipment - Selection and Design
P. 130

102  FLOW OF  FLUIDS

                EXAMPLE 6.7-(continued)                                              0.02517(0.02068)( low)( 1.2707)’  = 82.08 ft.
                   E  = 0.00015 ft,                                    hf14 = hf24 = hf34 =   (0.4)’
                   h  - sfLeZ = 0.0251fLQ’/D5  ft,                  Velocity head at discharge:
                     -g,x  D
                   hfl = hfl = h0,


                                                                    Total head at pumps:



                                                                           + 0.88 + 82.08 + 88.65
                                                                         = 345.36ft.
                              1.6364                                Power
                    = [ln(2.03(10W5)/D + 6.5/NR,]* ’
                                                                       = YQ&
                For line 45,                                           0.92(62.4)(10/3)345.36
                                                                       = 66,088 ft lb/sec
                   (NRJ4 = 31542 (3.333) = 105,140,                      120.2 HP,  89.6 kW.
                   f4  = 0.01881,
                         0.02517(0.01881)(4000)(3.333)’ = 88. 65 ft.
                   (hf )45 =      (0.75)5
                Procedure:
                1. As a first trial assume f, =fi = f3, and find  Q, = 1.266 from Eq.
                  (8).
                2.  Find Q,  and Q3 from Eqs. (6) and (7).
                3.  With these values of  the  Qz, find improved values of  the  and
                  hence improved values of  Q,  and Q3 froq Eqs. (6) and (7).
                4.  Check how closely Q, + Q2 + Q3 - 3.333 = 0.
                5.  If  check is not close enough, adjust the  value of  Q,  and repeat
                  the calculations.

                   The two trials shown following prove to be adequate.
                     Q,     02    Q,     Q,    10/3-0,   f,                  -  . -   . . - .
                                                                      138  Q2=1.2352*Ql*(Fl,F22^.5           !  im
                    1.2660  1.5757  0.4739  3.3156   0.0023   0.02069       Proved value
                    1.2707  1.5554  0.5073  3.3334   0.0001   0.02068   148  Q3=.3977SQl*(Fl,F3>’.5        !  imp
                                                                            roved value
                   Summary :                                          158  X=l8~-3-Ql-Q2-Q3 !  should he
                                                                            less than 8.9881
                          Line   A$,e   f      Q     h,               168  DISF  X,QliQ2,Q3
                          14   75,152  0.02068  1.2707  82.08         178  GOT#  48  !  choose another Val
                          24   60,121  0.02106  1.5554  82.08               ue of  121  if  condition of  ste
                          34   99,821  0.02053  0.5073  82.08               P  lS8  is not  5atisfierj
                          45   105,140  0.01881  3.3333  88.65        188  END.





                   EXAMPLE 6.8                                      Characteristics of the alternate pump drives are:
                    Economic  Optimum Pipe  Size for  Pumping  Hot  Oil  with  a   a.  Turbines  are  3600rpm,  exhaust  pressure  is  0.75bar,  inlet
                   Motor or Turbine Drive
                A  centrifugal pump  and  its  spare  handle  1000gpm of  an  oil  at   pressure is 20 bar,  turbine  efficiency is 45%. Value of  the high
                500°F.  Its  specific gravity  is  0.81  and  its  viscosity is  3.0cP.  The   pressure  steam  is  $5.25/10001bs;  that  of  the  exhaust  is
                length of  the line is 600 ft and its equivalent length with valves and   $0.75/1000 lbs.
                other fittings is 900 ft. There are 12 gate valves, two check valves,   b. Motors have efficiency of  90%, cost of  electricity is $0.065/kWh.
                and one control valve.                                 Cost data are:
                    Suction pressure at the pumps is atmospheric; the pump head
                exclusive of  line friction is 120 psi. Pump efficiency is 71%. Material   1. Installed cost of  pipe is 7.50 $/ft and that of  valves is 600D0.7 $
                of construction of  line and pumps is 316 SS. Operation is 8000 hr/yr.   each, where D is the nominal pipe size in inches.
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