Page 189 - Chemical Process Equipment - Selection and Design
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7.6.  THEORY  AND  CALCULATIONS  OF  GAS  COMPRESSION  761



              EXAMPLE 7.9                                     Accordingly,
              Selection of a Centrifugal Compressor
           A hydrocarbon mixture with molecular weight 44.23 is raised from   n-1  k-1-   Q.135
           41°F and  20.1 psia  to  100.5 psia  at  the  rate  of  2400 lb mol/hr.  Its   n   -  krlp   -  1.135(0.77)  = 0.1545.
           specific  heat  ratio  is  k = 1.135  and  its  inlet  and  outlet
           compressibiiities are estimated as z, = 0.97 and zz = 0.93. A size of   Using Eq. (7.35) for the polytropic head,
           compressor  will  be  selected  from  Table  7.6  and  its  expected
           performance will be calculated:                                               n - l)/n

              2400 Bb  moli/hr = 1769 Ib/min,
                                                                               1544
                          10,260 cfm                                = 0.95(-) 1.135 ( -)(501)[j0.1s4s   - 11
                                                                         0.135  44.23
           From Table 7.6. the smallest compressor for this gas rate is  # 38M.   = 39430 ft.
           Its characteristics are
                                                                  From Figure 7.26(a), the max head per stage is 9700, and from
              rb= 8100 rpm at 10-12  K ft/stage               Figure 7.26(b) the min number of  stages is about 4.5. Accordingly,
                                                              use five stages with standard 10,000 ft/stage impellers. The required
              q, = 0.77
                                                              speed with the data of  Table 7.6 is
                                                                  speed = 8100~39430/10,000(5) = 7190 rpm.
                                         ----t  100.5
                                                                  Power absorbed by the gas is
                                         P,  = 100.5
                                         2, = 0.93

                    2, := 0.97                                Friction losses -3%  max;
                    1769  iblrnin
                    10260 cfm                                     :.  total power input = 2745/0.97 = 2830 MP max.




           or alternately in terms of the isentropic efficiency by   stages, accordingly, the compression ratio of each stage is

                                                       (7.54)
           so that                                            Example  7.11  works  out  a  case  involving  a  nonideal  gas  and
                                                              interstage pressure losses.
              T2 = a, + (AT),/V, = Tl{l + (1/17,)[(q/Pl)(k-')/k - 1 I>.  (7.55)   In centrifugal compressors with  all stages in the same shell, the
                                                              allowable head nse per stage is stated in Table 7.6 or correlated in
              The  final  temperature  is  read  off  directly  from  a  thermo-   Figure 7.26. Example 7.9 utilizes these data.
           dynamic diagram when  that  method  is  used  for  the  compression
           calculation, as in Example 7.7. A temperature calculation is made   Volumetric Eficieney.  For  practical  reasons,  the  gas  is  not
           in Example 7.10. Such determinations also are made by the general   completely  discharged  from  a  cylinder  at  each  stroke  of  a
           method for nonideal gases and mixtures as in Example 7.8 and for   reciprocating machine.  The  clearance  of  a  cylinder  is  filled with
           ideal gases in Example 7.4.                        compressed gas which reexpands isentropically on the return stroke.
                                                              Accordingly, the gas handling capacity of the cylinder is less than
                                                              the  product  of  the cross section by  the  length of  the  stroke.  The
              Compression Ratio,  In order  to save on equipment cost, it is   volumetric efficiency is
           desirable to use as few stages of  compression as possible. As a rule,
           the  compression ratio  is limited by  a practical desirability to keep   suction gas volume
           outlet temperatures below 300°F or so to minimize the possibility of   nu = cylinder displacement
           ignition  of  machine  lubricants,  as  well  as  the  effect  that  power   = 1 -L[(P2/5)'"G - 11,   (7.57)
           requirement  goes  up  as  outlet  temperature  goes  up.  Typical
           compression ratios of  reciprocating equipment are:   where
                                                                         clearance volume
                                                                   = cylinder displacement volume .
                     Large pipeline compressors   1.2-2.0
                     Process cornpressors   1.5-4.0
                     Small units          up to 6.0           For  a  required  volumetric  suction  rate  Q  (cfm),  the  required
                                                              product of  cross section A, (sqft), stroke length L, (ft), and speed N
              For rninimiim equipment cost, the work requirement should be   (rpm) is given by
           the  same  for  each  stage.  For  ideal  gases  with  no  friction  losses
           between  stages,  this  implies  equal  compression  ratios.  With  n   A,L,N=  Q/%.           (7.58)
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