Page 41 - Circuit Analysis II with MATLAB Applications

Other Second Order Circuits

or

ksin M = 287 (1.81)
Then with (1.77) and (1.81),
ksin M 287
--------------- = tan M = --------- = 57.4
kcos M 5
or
M = 1.53 rad = 89q

The value of the constant is found from (1.77), that is,
k
k = 5 cos 89q = 279.4
e
By substitution into (1.76), we obtain the total solution as

vt = 279.4e – 6.4t cos 4.8t + 89q + 2cos 6400t – 89.72q (1.82)

With MATLAB we get the plot shown in Figure 1.18.

Figure 1.18. Plot for vt of Example 1.6

1.8 Other Second Order Circuits

Second order circuits are not restricted to series RLC and parallel GLC circuits. Other second order
circuits include amplifiers and filters. It is beyond the scope of this text to analyze such circuits in
detail. In this section we will use the following example to illustrate the transient analysis of a second
order active low-pass filter.

1-29 Circuit Analysis II with MATLAB Applications
Orchard Publications