Page 81 - Circuit Analysis II with MATLAB Applications

Half-Power Frequencies - Bandwidth

This can be shown by multiplication of the two expressions in (2.31) and (2.32) and substitution into
(2.33).

Example 2.3

For the network of Figure 2.13, find:

a. Z 0

b. Q 0P

c. BW

d. Z 1

e. Z 2

Y G L ` C
– 1 1 mH
0.001: 0.4 PF
Figure 2.13. Network for Example 2.3

Solution:

a.
1
1
2
Z = ------- = -------------------------------------------------- = 25 u 10 8
0
–
–
LC
6
3
10
10
u
1 u
0.4 u
or
Z = 50000 r s
e
0
b.
4
Z C 5 u 10 u 0.4 u 10 – 6
0
Q 0P = ---------- = ------------------------------------------------ = 20
3
G
–
10
c.
Z 50000
0
BW = --------- = --------------- = 2500 = rad s
e
Q 0P 20
d.
BW
Z = Z – --------- = 50000 1250 = 48750 rad s
–
e
1
0
2
e.
--------- =
Z = Z + BW 50000 + 1250 = 51250 rad s
e
2 0 2
Circuit Analysis II with MATLAB Applications 2-15
Orchard Publications