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Radio and Television Receivers


         Example 2.4

         A radio receiver with a parallel GLC  circuit whose inductance is L =  0.5 mH  is tuned to a radio
         station transmitting at 810 KHz  frequency.

         a. What is the value of the capacitor of this circuit at this resonant frequency?

         b. What is the value of conductance   if Q 0P  =  75 ?
                                           G
         c. If a nearby radio station transmits at 740 KHz  and both signals picked up by the antenna have the
           same current amplitude   (PA ), what is the ratio of  the  voltage  at  810 KHz   to  the  voltage  at
                                  I
           740 KHz  ?
         Solution:

         a.
                                                         1
                                                    2
                                                   Z =  -------
                                                    0   LC
           or
                                                         1
                                                 f 0 2  =  ----------------
                                                         2
                                                       4S LC
           Then,
                                                    1
                                  C =  ----------------------------------------------------------------------- =  77.2 pF
                                                               3 2
                                          2
                                       4S 0.5 u  10 – 3  u     810 u  10
         b.
                                                         Z C
                                                          0
                                                  Q   =  ----------
                                                   0P     G
           or
                                                       5
                                  2Sf C    2S u  8.1 u  10 u  77.2 u  10 – 12  –
                                     0
                             G =  --------------- =  ---------------------------------------------------------------------- =  5.4 P:  1
                                   Q 0P                75
         c.
                                                      I
                                                            I
                                              I
                                                                     I
                              V 810 KHz  =  ----------------------- =  ----- =  ---- =  --------------------------- 6  (2.39)
                                          Y
                                                                         –
                                                      Y
                                                           G
                                                                       10
                                                                 5.24 u
                                                       0
                                            810 KHz
           Also,
                                                             I
                                             V 740 KHz  =  -----------------------
                                                         Y
           where                                           740 KHz
                                                       2
                                                                  1 ·
                                         Y 740 KHz  =  G +  §  ©  ZC –  ------- ¹  2
                                                                 ZL
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