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128  Complementarity and Variational Inequalities in Electronics


                           which is equivalent to the variational inequality VI(M,q, ), that is,

                                      2                                     2
                                 I ∈ R : MI + q,v − I +  (v) −  (I) ≥ 0,∀v ∈ R ,    (4.119)
                           with M and q as in (4.106) and   as in (4.117).Here

                                                 2
                                       D( ) ∞ = R ,  ∞ ≡  , N(M, ) = ker{M},
                           and thus

                                                                         2
                                 D( ) ∞ ∩ ker{M}∩ N(M, ) = ker{M}={v ∈ R : v 2 =−v 1 }.
                           Let v ∈ ker{M}, v 
= 0. Then

                                     q,v +   ∞ (v) = v 2 (E 2 − E 1 ) + ϕ PD (−v 1 ) + ϕ PD (v 2 )
                                                 = v 2 (E 2 − E 1 ) + 2ϕ PD (v 2 ).

                           Therefore, if v 2 > 0, then

                                         q,v +   ∞ (v) = v 2 (E 2 − E 1 ) + 2ν 1 v 2 > 0,

                           whereas if v 2 < 0, then

                                        q,v +   ∞ (v) =−v 2 (2|ν 2 |− (E 2 − E 1 )) > 0.

                           We may then apply Corollary 8, which ensures that system (4.119) has at least
                           one solution.
                                     ∗ ∗ T
                                 ∗
                              If I = (i i ) is a solution of system (4.119), then from the first relation
                                     1 2
                                                                       ∗
                                                                               ∗
                                                                           ∗
                           in part (c) of Corollary 8 we deduce that the current i = i + i through the
                                                                           1   2
                           resistor R is uniquely determined.
                              So, for a driven time-dependent input t  à  u(t), the time-dependent current
                               ∗
                           t  à  i (t) through the resistor R is given by
                                                   ∗
                                                         ∗
                                                               ∗
                                                  i (t) = i (t) + i (t),            (4.120)
                                                               2
                                                         1
                                      ∗
                                           ∗
                           where I = (i (t),i (t)) is a solution of VI(M,q(t), ) with
                                 ∗
                                      1    1

                                                         E 1 − u(t)
                                                 q(t) =            ,
                                                         E 2 − u(t)
                           and the output-signal V o (see Fig. 4.8) can then be determined by the formula
                                                                ∗
                                                 V o (t) = u(t) − Ri (t).
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