Page 409 - Design of Reinforced Masonry Structures
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6.60                       CHAPTER SIX

           Example 6.3  A 20-ft-high, 8-in.-nominal, solidly grouted, concrete masonry wall is
                                                           2
           to be designed to resist out-of-plane load due to wind = 20 lb/ft  and due to earth-
                                                     2
                       2
           quake = 42 lb/ft  (Fig. E6.3A). The wall weighs 84 lb/ft  per linear foot and carries
           a superimposed dead roof load of 350 lb/ft and a roof live load of 240 lb/ft length of
           the wall. The roof is supported on a ledger beam attached to the wall, which creates
           an eccentricity of 4 in. from the center line of the wall. Determine the reinforcement
           (Grade 60) requirements for this wall. Assume that the wall is classified as SDC D and
                       2
            ′ f = 2000 lb/in. .
            m
                                           D = 350 lb/ft
                                           Lr = 240 lb/ft
                                                 e = 4"  Roof


                                                     Ledger
                                                     beam
                     Lateral loads                8" Nominal
                                                  CMU wall
                     Wind: 20 pst
                                                  As = ?
                                                               20'
                   Seismic: 42 pst











                   FIGURE E6.3A

           Solution
           Given:
             Wall height = 20 ft

             Wall thickness = 8 in. nominal (7.625 in. actual)
             Eccentricity of superimposed load = 4 in.
             Roof dead load = 350 lb/ft of wall
             Roof live load = 240 lb/ft of wall
                                          1
             Dead weight of wall at midheight = 84( /  × 20) = 840 lb
                                           2
                            2
             Wind load = 20 lb/ft  on the wall area (normal to wall), ASD-level load
             Seismic load F  = 42 lb/ft  (normal to wall), strength-level load
                                2
                        p
              f m ′ = 2000 lb/in. 2
                                                  2 2
                        )
             E = (900 )(  f ′ = (900 )(2000 )  = ,800 000 lb lb/in. = 1800  kips/in. 2
                                    1
                                        ,
              m        m
             Convert seismic load to ASD-level load to compare it with the wind load. ASD-level
                                           2
                                   2
           seismic load = 0.7(42) = 29.4 lb/ft  > 20 lb/ft  (wind).
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