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166   4. Particular Determinants

                       β 2i,2i = λ ii ,  i ≥ 1,
                   β 2i+1,2j+1 = λ ij ,  0 ≤ j ≤ i,
                     β 2i+2,2j = λ i+1,j − λ ij ,  1 ≤ j ≤ i +1,    (4.13.6)
                                i  	  i + j
                         λ ij =            ;
                              i + j   2j
                              1
                         λ ii = ,  i > 0;  λ i0 =1,i ≥ 0.           (4.13.7)
                              2
          The functions λ ij and f r (x) appear in Appendix A.10.
          Theorem 4.60.

                                    M = NKN .
                                              T
          Proof. Let
                                G =[γ ij ] n = NKN .                (4.13.8)
                                                  T
          Then
                                   G = NK N    T
                                            T
                                     T
                                       = NKN  T
                                       = G.
          Hence, G is symmetric, and since M is also symmetric, it is sufficient to
          prove that α ij = γ ij for j ≤ i. There are four cases to consider:

           i. i, j both odd,
          ii. i odd, j even,
          iii. i even, j odd,
          iv. i, j both even.
          To prove case (i), put i =2p+1 and j =2q+1 and refer to Appendix A.10,
          where the definition of g r (x) is given in (A.10.7), the relationships between
          f r (x) and g r (x) are given in Lemmas (a) and (b) and identities among the
          g r (x) are given in Theorem 4.61.

                      α 2p+1,2q+1 = u 2q+2p + u 2q−2p
                                   N

                                       -                     .
                                =    a j f 2q+2p (x j )+ f 2q−2p (x j )
                                  j=1
                                   N

                                       -                 .
                                =    a j g q+p (x j )+ g q−p (x j )
                                  j=1
                                    N

                                =2    a j g p (x j )g q (x j ).     (4.13.9)
                                   j=1
          It follows from (4.13.8) and the formula for the product of three matrices
          (the exercise at the end of Section 3.3.5) with appropriate adjustments to
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