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The Schottky effect                        93




                                                                             Fig. 6.4
                                                                             The ‘image charge’ theorem. The
                               x                   x  x  x                   effect of a plane conductor on the
                                                                             static field due to a charged particle is
                                                                             equivalent to a second, oppositely
                               Conducting         Remove plane               charged, particle in the mirror image
                               plane              add + charge               position.



                         Energy                      x
                                                      0


                               Metal–vacuum            B   Image
                               interface                   field
                        x

                            A                        A
                          ) a (                     ) b (

                                                                             Fig. 6.5
                                                                             The Schottky effect. (a) Potential at
                                                                             metal–vacuum interface. A denotes
                                                      Summarization          the bottom of the potential well.
                                                                             (b) Potential changed by image
                                                                             charge field. (c) Potential due to
                                                                             applied anode voltage in vacuum
                                                                             region. (d) Total potential field
                                                                             showing reduction in height of the
                          ) c (                     ) d (                    potential barrier compared with (a).

               In the above calculation, we took the potential energy as zero at x = ∞ to
            agree with the usual conventions of electrostatics, but remember that our zero
            a short while ago was that of a valence electron at rest. Hence, to be consistent,
            we must redraw the energy diagram inside and outside the metal as shown
            in Fig. 6.5(a). If we include now the effect of the mirror charges, then the  ∗  Note that the curve between A and
                                                                  ∗
            potential barrier modifies to that shown in Fig. 6.5(b).          B does not satisfy eqn (6.40). This is
                                                                             because the concept of a homogeneous
               In the absence of an electric field this change in the shape of the potential
                                                                             sheet is no longer applicable when x
            barrier has practically no effect at all. But if we do have electric fields, the  is comparable with the interatomic dis-
            small correction due to mirror charges becomes significant.       tance. The energy is, however, given for
               For simplicity, let us investigate the case when the electric field is con-  x = 0 (an electron resting on the sur-
                                                                             face must have the same energy as an
            stant. Then,
                                                                             electron at rest inside the metal); so we
                                                                             simply assume that eqn (6.40) is valid for
                                      V(x)=–eE x,                     (6.41)  x > x 0 and connect the points A and B by
                                                                             a smooth line.
            as shown in Fig. 6.5(c). If both an electric field is present and the mirror charges
            are taken into account, then the potentials should be added, leading to the po-
            tential barrier shown in Fig. 6.5(d). Clearly, there is a maximum that can be
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