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then:

                                                          n  
                                                       P I A k  =  P A(  n )
                                                          k=1  

                             Pb. 10.10 Find the probability that a positive integer randomly selected will
                             be non-divisible by:
                                a. 2 and 3.
                                b. 2 or 3.
                             Pb. 10.11 Show that the expression for Eq. (10.36) simplifies to:


                                                                            n
                                                      n
                                                               n
                                PA(  ∪ A ∪…∪   A ) =  C P A(  ) − C PA(  ∩ A ) +  C PA(  ∩ A ∩ A ) −
                                   1    2        n   1    1   2    1   2    3   1    2   3
                                                        −
                                                 …+ ( 1−  ) n 1 PA(  ∩  A ∩…∩  A )
                                                             1    2       n
                             when the probability for the intersection of any number of events is indepen-
                             dent of the indices.
                             Pb. 10.12 A filing stack has n drawers, and a secretary randomly files m-let-
                             ters in these drawers.
                                a. Assuming that m > n, find the probability that there will be at least
                                   one letter in each drawer.
                                b. Plot this probability for n = 12, and 15 ≤ m ≤ 50.
                                                                                    th
                              (Hint: Take the event A to mean that no letter is filed in the j drawer and
                                                   j
                             use the result of Pb. 10.11.)






                             10.4 Conditional Probability

                             The conditional probability of an event A assuming C and denoted by  PAC(  )
                             is, by definition, the ratio:


                                                              PA ∩  C)
                                                                (
                                                      PAC) =                              (10.37)
                                                        (
                                                                PC ()
                             Example 10.7
                             Considering the events E, O, B, C as defined in Section 10.2 and the above def-
                             inition for conditional probability, find the probability that the number of
                             spots showing on the die is even, assuming that it is equal to or greater than 3.


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