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            052184472Xc09  CUNY148/Severini  June 2, 2005  12:8





                            268                       Approximation of Integrals

                            or,
                                                      1  −  1         1  1        1
                                                          z
                                                           3
                                           ¯
                                           (z) = φ(z)  z  
   = φ(z)   −    + O
                                                           1
                                                    1 + O            z   z 3     z  5
                                                           z  4
                            as z →∞.
                              Note that this approach may be continued indefinitely, leading to the result that
                                               1    1   3            k  (2k)!  1      1

                                    ¯
                                     (z) = φ(z)  −    +   + ··· + (−1)         + O
                                                                       k
                                                z  z 3  z 5           2 k! z 2k+1    z 2k+2
                            as z →∞, for any k = 0, 1, 2,....
                                                      9.4 Watson’s Lemma

                            Note that an integral of the form
                                                         ∞

                                                            α
                                                           t exp(−nt) dt,
                                                        0
                            where α> −1 and n > 0, may be integrated exactly, yielding

                                                    ∞                 (α + 1)
                                                       α
                                                      t exp(−nt) dt =   α+1  .
                                                   0                   n
                              Now consider an integral of the form
                                                         ∞

                                                           h(t)exp(−nt) dt
                                                        0
                            where h has an series representation of the form
                                                                ∞
                                                                     j
                                                         h(t) =   a j t .
                                                               j=0
                            Then, assuming that summation and integration may be interchanged,
                                     ∞                  ∞     ∞                 ∞

                                                                                     ( j + 1)
                                                                 j
                                       h(t)exp(−nt) dt =  a j   t exp(−nt) dt =   a j       .
                                    0                  j=0   0                 j=0    n  j+1
                              Note that the terms in this series have increasing powers of 1/n; hence, if n is large,
                            the value of the integral may be approximated by the first few terms in the series. Watson’s
                            lemma is a formal statement of this result.
                            Theorem 9.12 (Watson’s lemma). Let h denote a real-valued continuous function on
                            [0, ∞) satisfying the following conditions:
                               (i) h(t) = O(exp(bt)) as t →∞ for some constant b
                              (ii) there exist constants c 0 , c 1 ,..., c m+1 ,a 0 , a 1 ,..., a m+1 ,

                                                       −1 < a 0 < a 1 < ··· < a m+1
                            such that
                                                                 m

                                                         ˆ           a j
                                                         h m (t) =  c j t
                                                                j=0
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