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            052184472Xc09  CUNY148/Severini  June 2, 2005  12:8





                                                    9.4 Watson’s Lemma                       273

                                            Table 9.3. Approximations in Example 9.6.

                                                                          Relative
                                       z      ν      Exact     Approx.    error (%)

                                       1.5     2     0.136     0.174      27.5
                                       1.5     5     0.0970    0.113      16.8
                                       1.5    10     0.0823    0.0932     13.4
                                       1.5    25     0.0731    0.0814     11.4
                                       2.0     2     0.0918    0.0989      7.8
                                       2.0     5     0.0510    0.0524      2.7
                                       2.0    10     0.0367    0.0372      1.3
                                       2.0    25     0.0282    0.0284      0.6
                                       3.0     2     0.0477    0.0484      1.4
                                       3.0     5     0.00150   0.00150     0.3
                                       3.0    10     0.00667   0.00663     0.6
                                       3.0    25     0.00302   0.00300     0.7



                                      2
                        where c ν = 1 + z /ν.To use Theorem 9.13, we may use the expansion
                                               √
                                         1      c ν         1         1     3    1      2
                        (1 − exp(−2t)/c ν ) −  2 = √  1 −      t +        +            t +· · · .
                                              (c ν − 1)   c ν − 1   c ν − 1  2 (c ν − 1) 2
                        Note, however, that as ν →∞, c ν → 1, so that Theorem 9.13 can only be applied if, as
                                2
                        ν →∞, z /ν remains bounded away from 0. Hence, we assume that z is such that
                                                 z 2
                                                   = b + o(1) as ν →∞,
                                                 ν
                        for some b > 0.
                          Applying Theorem 9.13 yields the result

                             ∞         −(ν+1)

                                    2
                              (1 + y /ν)  2  dy
                            z
                                 1     1       1    1   1       1     3   1       1       1
                             =      √           −         +         +              + O
                                (  ν−1 )  (c ν − 1) ν  c ν − 1 ν 2  c ν − 1  2 (c ν − 1) 2  ν 3  ν 4
                               c ν  2
                                     2
                        as ν →∞ and z /ν → b > 0.
                          When this expansion is used to approximate the integral, we will be interested in the value
                        for some fixed values of ν and z. Hence, it is important to understand the relevance of the
                                               2
                        conditions that ν →∞ and z /ν → b > 0in this case. Since we are considering ν →∞,
                        we expect the accuracy of the approximation to improve with larger values of ν.However,
                                                                        2
                        for a fixed value of z,a larger value of ν yields a value of z /ν closer to 0. Hence, if ν is
                        larger, we expect high accuracy only if z is large as well. That is, when approximating tail
                        probabilities, we expect the approximation to have high accuracy only when approximating
                        a small probability based on a moderate or large degrees of freedom.
                          Table 9.3 gives the approximations to the tail probability Pr(T ≥ z), where T has a
                        t-distribution with ν degrees of freedom, given by

                             ((ν + 1)/2)  1    1      1     1   1      1     3    1      1
                           √            ν−1  √         −          +        +                ,
                             (νπ) (ν/2)  (  2  )  (c ν − 1) ν  c ν − 1 ν 2  c ν − 1  2 (c ν − 1) 2  ν 3
                                       c ν
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