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book   Mobk070    March 22, 2007  11:7








                                               INTEGRAL TRANSFORMS: THE LAPLACE TRANSFORM           103
                   and from Eq. (6.8)

                                                          1       1
                                                   Y =        −
                                                        s + 1   s + 3                           (6.42)
                                                   y = e  −t  − e −3t


                   6.4    SOME IMPORTANT THEOREMS
                   6.4.1  Initial Value Theorem


                                               ∞

                                           lim    f (t)e −st dt = sF(s ) − f (0) = 0            (6.43)

                                          s →∞
                                              t=0
                   Thus

                                                   lim sF(s ) = lim f (t)                       (6.44)
                                                  s →∞         t→0

                   6.4.2  Final Value Theorem
                   As s approaches zero the above integral approaches the limit as t approaches infinity minus
                   f (0). Thus

                                                lim    sF(s ) = lim  f (t)
                                                                                                (6.45)
                                                s → 0        t →∞


                   6.4.3  Convolution
                   A very important property of Laplace transforms is the convolution integral. As we shall see
                   later, it allows us to write down solutions for very general forcing functions and also, in the
                   case of partial differential equations, to treat both time dependent forcing and time dependent
                   boundary conditions.
                        Consider the two functions f (t)and g(t). F(s ) = L[ f (t)] and G(s ) = L[g(t)]. Because
                   of the time shifting feature,
                                                                 ∞

                                        e −s τ G(s ) = L[g(t − τ)] =  e −st g(t − τ)dt          (6.46)
                                                                t=0
                                                    ∞

                                        F(s )G(s ) =   f (τ)e  −s τ  G(s )dτ                    (6.47)
                                                   τ=0
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