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                                                                                  6.6 Office Studies of Pipe Networks  209
                                             Although the network in Example 6.3 is simple, it cannot be solved conveniently by
                                         algebraic methods, because it contains two interfering hydraulic constituents: (a) a crossover
                                         (pipe 4) involved in more than one circuit and (b) a series of takeoffs representing water used
                                         along the pipelines, fire flows through hydrants, or supplies through to neighboring circuits.




                     EXAMPLE 6.3   ANALYSIS OF A WATER NETWORK USING THE RELAXATION METHOD
                     OF BALANCING HEADS
                                         Balance the network of Fig. 6.12 by the method of balancing heads.


                                                           Q 0     Q 1      Q 2      Q 3               Take-off
                                               Inflow
                                              2.0
                                                          1.00     1.21     1.24    1.25                  0.6
                                                    A                 1.     2,000´ 12˝              B

                                                Q 3  .75  1,000´ 8˝                                 Q 3  .65  1,000´ 8˝

                                                Q 2  .76                     I                      Q 2  .64

                                                Q 1  .79                                            Q 1  .61
                                                     3.                                                  2.
                                                Q 0  1.00  Q 0     Q 1      Q 2      Q 3            Q 0  0.40
                                                          0.50     0.36     0.36    0.36             C  Take-off
                                                                      4.    2,000´ 8˝                     0.6

                                                Q 3  .39  1,000´ 6˝                                 Q 3  .41  1,000´ 6˝

                                                Q 2  .40                     II                     Q 2  .40

                                                Q 1  .43                                            Q 1  .37
                                                     6.                                                  5.
                                                Q 0  0.50  Q       Q        Q        Q              Q 0  0.30
                                                                             2
                                                                     1
                                                                                      3
                                                            0
                                                    D     0.30     0.23     0.20    0.19             E
                                              Take-off 0.2          7.    2,000´ 6˝                     0.6
                                                                                                        Take-off
                                                                      All flows are in MGD
                                             Figure 6.12 Plan of Network Analyzed by the Method of Balancing Heads (Example 6.3)
                                             Conversion factors: 1 MGD   3.785 MLD; 1   1 ft   0.3048; 1   1 in.   25.4 mm

                                         Solution:
                                         The schedule of calculations (Table 6.4) includes the following:
                                             Columns 1 to 4 identify the position of the pipes in the network and record their length and di-
                                         ameter. There are two circuits and seven pipes. Pipe 4 is shared by both circuits; “a” indicates this in
                                         connection with circuit I; “c” does so with circuit II. This dual pipe function must not be overlooked.
                                             Columns 5 to 9 deal with the assumed flows and the derived flow correction. For purposes of
                                         identification the hydraulic elements Q, s, H, and q are given a subscript zero.
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