Page 129 - T. Anderson-Fracture Mechanics - Fundamentals and Applns.-CRC (2005)
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1656_C003.fm  Page 109  Monday, May 23, 2005  5:42 PM





                       Elastic-Plastic Fracture  Mechanics                                         109































                       FIGURE 3.8 Nonlinear energy release rate.


                       Thus if the plate in Figure 3.8 is in load control, J is given by

                                                          J =   dU  *                          (3.14)
                                                               da   P


                       If the crack advances at a fixed displacement, F = 0, and J is given by

                                                         J =−   dU                             (3.15)
                                                                da  ∆

                       According to Figure 3.8, dU* for load control differs from −dU for displacement control by the
                       amount  1 2  dPd∆, which is vanishingly small compared to dU. Therefore, J for load control is equal
                       to J for displacement control. Recall that we obtained this same result for G in Section 2.4.
                          By invoking the definitions for U and U*, we can express J in terms of load and displacement:
                                                            ∂  P   
                                                       J =   ∫ 0  ∆ dP   P
                                                            a ∂

                                                            P  ∆                                (3.16)
                                                              ∂ 
                                                         =    ∫      dP
                                                           0   a ∂  P
                       or
                                                             ∂  ∆  
                                                                   ∆
                                                       J =−   ∫  Pd  
                                                             a ∂
                                                               0
                                                                     ∆
                                                                                                 (3.17)
                                                            ∆  ∂ P
                                                        =−    ∫      d∆
                                                            0  a ∂   ∆
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