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                       18                                    Fracture Mechanics: Fundamentals and Applications


                       1.5  A BRIEF REVIEW OF DIMENSIONAL ANALYSIS

                       At first glance, a section on dimensional analysis may seem out of place in the introductory chapter
                       of a book on fracture mechanics. However, dimensional analysis is an important tool for developing
                       mathematical models of physical phenomena, and it can help us understand existing models. Many
                       difficult concepts in fracture mechanics become relatively transparent when one considers the
                       relevant dimensions of the problem. For example, dimensional analysis gives us a clue as to when
                       a particular model, such as linear elastic fracture mechanics, is no longer valid.
                          Let us review the fundamental theorem of dimensional analysis and then look at a few simple
                       applications to fracture mechanics.

                       1.5.1 THE BUCKINGHAM Π-THEOREM

                       The first step in building a mathematical model of a physical phenomenon is to identify all of the
                       parameters that may influence the phenomenon. Assume that a problem, or at least an idealized
                       version of it, can be described by the following set of scalar quantities: {u, W , W ,…, W }. The
                                                                                                n
                                                                                          2
                                                                                      1
                       dimensions of all quantities in this set is denoted by {[u], [W ], [W ],…, [W ]}. Now suppose that
                                                                                    n
                                                                            2
                                                                        1
                       we wish to express the first variable u as a function of the remaining parameters:
                                                      u   f = ( W  W ,  , W ,  )                 (1.6)
                                                             1  2    n
                       Thus, the process of modeling the problem is reduced to finding a mathematical relationship that
                       represents f as best as possible. We might accomplish this by performing a set of experiments in
                       which we measure  u while varying each W independently. The number of experiments can be
                                                           i
                       greatly reduced, and the modeling processes simplified, through dimensional analysis. The first
                       step is to identify all of the fundamental dimensional units (fdu’s) in the problem: {L , L ,…, L }.
                                                                                                   m
                                                                                           1
                                                                                              2
                       For example, a typical mechanics problem may have {L  = length, L  = mass, L  = time}. We can
                                                                                       3
                                                                    1
                                                                              2
                       express the dimensions of each quantity in our problem as the product of the powers of the fdu’s;
                       i.e., for any quantity X, we have
                                                      X
                                                     [] =  L  a  L  a 1  2 , , L  a m            (1.7)
                                                           1  2      m
                       The quantity X is dimensionless if [X] = 1.
                          In the set of Ws, we can identify m primary quantities that contain all of the fdu’s in the problem.
                       The remaining variables are secondary quantities, and their dimensions can be expressed in terms
                       of the primary quantities:


                                               =
                                                                  m
                                                       1
                                         [ W  mj ] [ W  1 ] a mj+  ()  ,   ,[ W  m ] a mj+  ( )  ( j  =  , ,  , n 12  −  m  (1.8)
                                             +
                       Thus, we can define a set of new quantities π  that are dimensionless:
                                                            i
                                                              W
                                                                 +
                                                    π =         mj                                (1.9)
                                                     i
                                                        W
                                                         1 a mj+  , , W  m a mj m+ 1 ()  ( )
                       Similarly, the dimensions of u can be expressed in terms of the dimensions of the primary quantities:

                                                       u
                                                         =
                                                      [] [ W  ] , ,[ W  ] a m                   (1.10)
                                                              a 1
                                                            1       m
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