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320                    Fundamentals of Probability and Statistics for Engineers

           particular case involved. In practice, common values for    are 0.001, 0.01, and
           0.05; a value of    between 5% and 1% is regarded as almost significant; a value
           between 1% and 0.1% as significant; and a value below 0.1% as highly significant.
             Let us now give a step-by-step procedure for carrying out the   2  test when
           the distribution of a population X  is completely specified.
           .  Step  1:  divide  range  space  X  into  k  mutually  exclusive  and  numerically
            convenient intervals A i , i ˆ  1, 2, ..., k. Let n i  be the number of sample values
            falling into A i . As a rule, if the number of sample values in any A i  is less than
            5, combine interval A i  with either A i 1 or A i 1 .
                                                  ‡

           .  Step 2: compute theoretical probabilities P(A i ) ˆ  p i , i ˆ  1, 2, ..., k, by means
            of the hypothesized distribution.
           .  Step 3: construct d as given by Equation (10.7).
           .  Step  4:  choose  a  value  of    and  determine  from  Table  A.5  for  the   2
            distribution of (k    1) degrees of freedom the value of   2  .

                                                             k 1,
           .  Step 5: reject hypothesis H  if d >  2  . Otherwise, accept H.

                                           k 1,




             Example 10.1. Problem: 300 light bulbs are tested for their burning time t (in
           hours), and the result is shown in Table 10.1. Suppose that random burning
           time T is postulated to be exponentially distributed with mean burning time
           1/  ˆ  200 hours; that is,   ˆ :
                                    0 005, per hour, and
                               f …t†ˆ 0:005 e  0:005t ;  t   0:         …10:8†
                                T
           Test this hypothesis by using the   2  test at the 5% significance level.
             Answer: the necessary steps in carrying out the   2  test areindicatedinTable 10.2.
           The  first  column  gives  intervals  A i ,  which  are  chosen  in  this  case  to  be  the
           intervals of t given in Table 10.1. The theoretical probabilities P(A i ) ˆ  p i  in the
           third column are easily calculated by using Equation (10.8). For example,
                               Z  100
                   p 1 ˆ P…A 1 †ˆ  0:005 e  0:005t  dt ˆ 1   e  0:5  ˆ 0:39;
                                0
                                 200
                               Z
                   p 2 ˆ P…A 2 †ˆ  0:005 e  0:005t  dt ˆ 1   e  1    0:39 ˆ 0:24:
                                100
                                Table 10.1  Sample values for
                                       Example 10.1
                              Burning time, t       Number

                              t <  100                 121
                              100    t <  200          78
                              200    t <  300          43
                              300    t                 58
                                                    n ˆ  300









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