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Model Verification                                              321

                          Table 10.2  Table for   2  test for Example 10.1
                                                          2
                          Interval, A i  n i  p i   np i  n /np i
                                                          i
                          t <  100      121   0.39  117  125.1
                          100    t <  200  78  0.24  72   84.5
                          200    t <  300  43  0.15  45   41.1
                          300    t       58   0.22   66   51.0
                                        300   1.00  300  301.7
                          Note:  n i ,  observed  number  of  occurrences;  p i ,
                          theoretical P(A i ).

             For convenience, the theoretical numbers of occurrences as predicted by the
           model are given in the fourth column of Table 10.2, which, when compared
           with the value in the second column, give a measure of goodness of fit of the
                                        2
           model  to  the  data.  Column  5  (n /np i )  is  included  in  order  to  facilitate  the
                                        i
           calculation of d. Thus, from Equation (10.7) we have
                                 k   2
                                X   n
                             d ˆ     i    n ˆ 301:7   300 ˆ 1:7:
                                    np i
                                 iˆ1
           Now,  k ˆ  4.  From  Table A.5  for  the   2  distribution with three degrees of
           freedom, we find
                                        2  ˆ 7:815:
                                       3; 0:05

           Since d <  2  , we accept at the 5% significance level the hypothesis that the
                     3, 0 05
                       :
           observed data represent a sample from an exponential distribution with
             ˆ 0 005.
                .
             Example 10.2. Problem: a six-year accident record of 7842 California drivers
           is given in Table 8.2. On the basis of these sample values, test the hypothesis
           that X, the number of accidents in six years per driver, is Poisson-distributed
           with mean rate   ˆ  0 08 per year at the 1% significance level.
                             .
             Answer: since X  is discrete, a natural choice of intervals A i  is those centered
           around the discrete values, as indicated in the first column of Table 10.3. Note
           that interval x >  5 would be combined with 4 <  x    5 if number n 7 were less
           than 5.
             The hypothesized distribution for X  is

                                             x  0:48
                                 x   t
                              … t† e    …0:48† e
                      p X …x†ˆ        ˆ            ;  x ˆ 0; 1; 2; .. . :  …10:9†
                                 x!          x!






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