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326                    Fundamentals of Probability and Statistics for Engineers

                          Table 10.6  Table for   2  test for Example 10.4
                                                             2
                        Interval, A i  n i  p i     np i    n /np i
                                                             i
                        x    56        13   0.161   11.27   15.00
                        56 <  x    72  10   0.178   12.46    8.03
                        72 <  x    88  20   0.224   15.68   25.51
                        88 <  x    104  13  0.205   14.35   11.78
                        104 <  x    120  8  0.136    9.52    6.72
                        120 <  x        6   0.096    6.72    5.36
                                       70   1.0     70      72.40




           With intervals A i  defined as shown in the first column of Table 10.6, theoretical
           probabilities  P(A i )  now  can  be  calculated  with  the  aid  of  Table  A.3.  For
           example, the first two of these probabilities are


                                              56   83:6
                   P…A 1 †ˆ P…X   56†ˆ PU   p      ˆ F U … 0:990†
                                                 777:4
                         ˆ 1   F U …0:990†ˆ 1   0:8389 ˆ 0:161;

                   P…A 2 †ˆ P…56 < X   72†ˆ P… 0:990 < U   0:416†
                         ˆ‰1   F U …0:416†Š   ‰1   F U …0:990†Š

                         ˆ 0:339   0:161 ˆ 0:178:

             The information given above allows us to construct Table 10.6. Hence,
           we have

                                 k   2
                                X   n i
                            d ˆ         n ˆ 72:40   70 ˆ 2:40:
                                   np i
                                iˆ1
                                                           r
           The number  of degrees of freedom  in  this case is k      1 ˆ  6     1 ˆ  3.
                                                                     2
           Table A.5 thus gives
                                       2 3; 0:05  ˆ 7:815:

           Since  d <  2 3, 0 05  normal distribution N(83 6, 777 4) is acceptable at the 5%
                                                     .
                                                .
           significance level.
             Before leaving this section, let us remark again that statistic D in the  2  test is
                                                                         >
            2 -distributed only when n !1 . It is thus a large sample test. As a rule, n    50
           is considered satisfactory for fulfilling the large-sample requirement.







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