Page 275 - Fundamentals of Reservoir Engineering
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OILWELL TESTING                                    212

                     At the end of the flow test the well is closed in for a pressure buildup from which the
                     permeability is estimated as 610 mD. The available reservoir data and fluid properties
                     are listed below.

                     Drainage area A = 80 acres

                                       2

                     Geometry                  1



                                       φ    =.22       B o = 1.35 rb/stb
                                       h    = 15 ft    µ   =1 cp

                                                                     -6
                                            = .33 ft   c   = 21 × 10 /psi
                                       r w
                     1)   Analyse the test data to determine k and S using equ. (7.69) with the p D functions
                           evaluated using equ. (7.42) or (7.46)
                     2)   Repeat the analysis evaluating the p D function for transient flow conditions,
                           equ. (7.23).


                     EXERCISE 7.8 SOLUTION

               1)    The general multi-rate test analysis equation, (7.69) can be expressed as


                            p − p  )     n  q
                           ( i   wf n  = m    ∆  j  p  t  −  t  )  + mS
                              q n        j1 q n  D  ( D n  D −
                                                        j 1
                                         =
                     where m = 141.2 µ B o/kh

                                             '
                     and p D  t  n  −  t D j 1 )   = p D ( t ) can be evaluated as
                                             D
                            ( D
                                    −
                                                        4A
                           p D  ( ) 2 t′ +  1 2  ln t′ +  1 2 ln  −  1 2 p D(MDH) (t )              (7.46)
                              t′ =
                                                                       ′
                                    π
                               D
                                                DA
                                                                       DA
                                       DA
                                                         r γ  w 2
                     i.e.
                           p D  ( ) α −  1 2 p D(MDH) (t )                                          (7.73)
                              t′ =
                                                 ′
                                                DA
                               D
                                    .000264kt       .000264 610 t
                                                             ×
                     in which  t′ D  =         =
                                                               6
                                                              −
                                                    ××
                                     φµ  cr  w 2  .22 1 21 10 ×   (.33) 2
                                                          ×
                                  = 3.2 10 5  ( t hours )
                                       ×
                                          2
                     and      t DA  =  t ×  r / A = .01t (hours )
                                         w
                                     D
                     The p D functions, equ. (7.73), are evaluated in table 7.11 for all values of the time
                     argument required in the test, and for a variety of geometrical configurations of the
                     80 acre drainage area in order to investigate the sensitivity of the results to variation in
                     shape.
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