Page 333 - Fundamentals of Reservoir Engineering
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REAL GAS FLOW: GAS WELL TESTING                              268


                                       .0153 .832 .605 10    6
                                             ×
                                                         ×
                                                   ×
                                   p
                                  ∆=                           =  3.21 psi
                                               21200
                                                ×
                     Assuming a depletion type material balance, equ. (1.35), then
                                   G      p
                                                        4
                                                       −
                           ∆ G =       ∆  ( ) ≈ − 8 ×  10 G
                              p
                                 p/ Z i   Z
                                  i
                     Thus the use of the flow coefficients B and F, determined using the inflow equation in
                     the analysis is only very slightly pessimistic and in general provides a perfectly
                     acceptable approximation for highly productive wells such as the one described in this
                     exercise.

                                                           2
                                                                       2
               4)    For the assumed value of F = .047 psia /cp/(Mscf/d) , which was determined in the first
                     part of this exercise, the data for the plot of equ. (8.47) are listed in table 8.4, and the
                     plot itself shown as fig. 8.10.
                      4000
                               ∆ m(p) −  FQ  2 n                                  F = 0.030; A = 43 ACRES
                                    Q n
                                  2
                             (psia  / cp / Mscf/d)
                                                                                  F = 0.035; A = 60 ACRES






                                                                                 F = 0.040; A = 100 ACRES
                      3500







                                                                                 F = 0.047; A


                                                                 ∆ Q  j
                                                                        t ∆  j
                                                                 Q n
                      3000
                                        10           20            30

                     Fig. 8.10  Gas well test analysis assuming semi-steady state conditions and applying
                                equ. (8.47). Data; table 8.4
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