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Rapid Filtration                                                                                 361



            design. The spreadsheet may be used for design of a generic  Analysis
            under-drain system. Any combination of design variables may  The first task is to determine the air flow, that is, Q(air
            be selected to assess the effect on orifice flows and the  wash), required by the system. The second task is to cal-
                                                                  culate the pressure required at the outlet of the compres-
            pressure surface for the manifold system as a whole.
                                                                  sor. This is done as depicted in Figure 12.30. First the
              The objective of manifold design is to have uniform orifice
                                                                  pressure in the bubbles as they emerge from any given
            flowoverthewholemanifoldsystem.Themaximum orificeflow
                                                                  orifice is the static pressure of the water, that is,
            occurs at the first lateral and the first orifice while the minimum
                                                                  p(bubble) ¼ r w gh(water) plus atmospheric pressure. Then
            orifice flow is at the last lateral and the last orifice. The goal of  the pressure losses due to pipe friction must be calculated,
            manifold design is to minimize the difference between these two  for example, by Equation D.32, along with any other
            extremes in orifice flow but with the constraints that the sizes of  losses such as bends. This gives, by the Bernoulli relation,
            the header, laterals, orifices and the number of laterals, and  the pressure at the compressor exit. Knowing the absolute
            orifices should be within practical guidelines. As a corollary to  pressure at the compressor exit, the power can be calcu-
            objectiveofhavingnear-uniformorificeflowsisthatthepressure  lated by the equation for an adiabatic compression, that is,
            surface should have a minimum difference between the first  Equation D.75.
            and last orifice.                                      Solution
                                                                    1. Determine the air flow, Q(air wash),
            12.4.4.1.1  Hydraulic Grade Line for Backwash
                       System                                      Q(air-wash) ¼ Loading(air-wash)   A(filter)
            Figure 12.30, a three-dimensional perspective drawing for back-  ¼ 1:52 m = min (STP)   (4:267 m   6:096 m)
                                                                                   3
            wash, applies also to the air wash and illustrates the idea of          3                  3
                                                                            ¼ 39:52 m = min (1396 standard ft = min )
            relative pressure losses. For air, with pressure dimensions
            applied to the Bernoulli relation, we may think of a ‘‘pneumatic’’
                                                                    2. Determine the pressure, p 2 . which is the friction loss
            grade line (PGL, which has pressure as the energy dimension,  and other losses in the pipe system plus the water
                      3
            that is, FL=L ) instead of an hydraulic grade line (HGL, which  pressure at the depth of submergence, that is,
            has length as the energy dimension, that is, FL=F).
              The Darcy-Weisbach equation is applicable; for gases          p 2 ¼ Dp(friction) þ rwgh(water)
                                           2
            the form is D p ¼ f   (L=D)   r(gas)   (v =2). Equation D.23,
                                     0.5
            Q(orifice) ¼ A(orifice)C D [2gDh] , is for orifice flow. Table  where
            CDD.2 may be adapted as a spreadsheet solution to calculate
            the power of an adiabatic compression required for the com-                          v 2
                                                                                         L
                                                                            Dp(friction) ¼ f  r(air)     (D:43)
            pressor (default compressor and motor efficiencies for 0.70                   D      2g
            for each, respectively, are incorporated in the spreadsheet).
            The orifice coefficient of 0.61 is also a default value, as is, f,  3. Calculate the theoretical compressor power for an
            the pipe friction coefficient. The pressure for an air wash  adiabatic compression by Equation D.72, that is,
            system is determined by the water depth at the orifice, the
            Dp(orifice) for the required air flow per orifice, and the friction  P ¼ Q(air)   p 1   (k=(k   1){(p 2 =p 1 ) [(k 1)=k]    1}  (D:59)
            and minor losses through the laterals, manifold, and other
                                                                    4. Assume the compressor efficiency is say 0.7 and the
            pipes, which gives the pressure, p 2 for the compressor; p 1
            pressure is the ambient air pressure. The air flow, Q(air for  motor efficiency is 0.7 to calculate actual power
            one filter) combined with the ratio, p 2 =p 1 , and inlet tempera-  required by the compressor and the power required
                                                                      by an electric motor.
            ture, permits calculation of the compressor power.
                                                                  Comments
              Example 12.6 Compressor Flow and Pressure           The value of ‘‘P’’ can be calculated most expediently by
              for Air Wash                                        means of the spreadsheet, Table CDD.5.

              Given                                            12.4.4.2  Types of Backwash Systems
              Suppose a filter bed is 4.27   6.10 m (14   20 ft) plan area  The three kinds of backwash systems are (Monk, 1987) as
              and that the air wash capacity in terms of surface loading  follows: (1) direct pumping, (2) pump and reservoir, and (3)
                                2
                             3
                                              2
                                            3
              should be 1.524 m =m =min (STP) (5 ft =ft =min). Let tem-
              perature be 258C and let atmospheric pressure be sea  self backwashing. In direct pumping, filtered water is pumped
              level, 101,325 kPa. Let the depth of water in the filter  from the clear-well and pressurizes the under-drain system. In
              box be say 3.0 m (9.84 ft), that is, from the orifices to the  the ‘‘pump-and-reservoir’’ type, filtered water is pumped from
              crests of the backwash water troughs. Let the temperature  the clear-well to separate reservoir, usually elevated. A self
              be say 208C and assume an altitude of 1585 m (5200 ft).  backwashing system utilizes the head from a tailwater over-
              Required                                         flow with an associated intermediate reservoir before the
              Compressor flow capacity and discharge pressure and  clear-well. This intermediate reservoir has an overflow weir
              power.                                           to the clear-well that has high enough crest elevation to
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