Page 323 - Handbook of Structural Steel Connection Design and Details
P. 323

Partially Restrained Connections

                    308   Chapter Four

                       There are six bolts so the capacity is 6   28.3   169 kips > P , so shear does
                                                                         u
                       not govern. Bearing will control in the angles and not in the column flange
                       which is much thicker. The minimum angle thickness is therefore:
                                    R n sbearingd $  s2.4F u d 3 d 3 t $ 28.3 kips
                                                     28.3
                                                  t f min $   $ 0.27 in
                                                s0.75ds2.4ds58ds1d
                                                S use 2L 3 4 3 4 3 5/16 3 1 ft- 0 in
                      Number of required bolts:
                                           112
                                     N 5         5 3.95 bolts 1 use 4 bolts
                                         28.3/bolts
                      Check shear in net section:
                                                   1
                                       A ns 5 tc12 in 2 5a1 1  bd 5 6.6875t
                                                   16
                                             112>2
                           required  t $                  $ 0.32 in 1 use t 5 3>8 in
                                     0.75 3 0.6 3 58 3 6.6575
                                             S use 2L 4 3 4 3 3>8 3 1 ft- 0 in
                     9. Check if stiffeners in column are required: To avoid stiffeners, the column web
                       must be checked for
                      a. Compression zone
                         (1) K 1.3—local web yielding:
                                                 $ s1.0d s5 3 1.625 1 0.65ds36ds0.51d
                             P bf 5  s5k 1 t fb dF y c  3 t w c
                                5 161.1 kips

                         (2) K 1.4—web crippling:
                                               1.5
                                  2
                        P bf 5  135t we c11 3a t fb ba  t we b  d  F ye t ye
                                         d  t fe  B t we
                                               0.65    0.51    36 ? 0.55
                                         2
                             5 0.75 ? 135s0.51d c1 1 3a  ba  151 bd   $ 174.39 k ips
                                               14.31  0.855  B   0.51
                         (3) K 1.5—compression buckling of the web:
                                          3       4100s0.51d3236
                                 R n 5  4100 t w 2F yc  5       5 267 kips
                                          d c           11
                      Thus none of the capacities are exceeded and no stiffeners are required!
                      b. Tension zone:
                         (1) K 1.2—local flange bending:
                                                             2
                                         2
                             P bf 5   b 6.25 ? t fc ? F yc 5 0.9 ? 6.25s0.855d ? 36 5 148.0 kips
                      Thus P  equals the required strength and no tension stiffener are required!
                            bf
                      The final design is shown in Fig. 4.17.



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