Page 199 - Introduction to Computational Fluid Dynamics
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                                                                2D CONVECTION – COMPLEX DOMAINS
                                                                        ξ 2        May 25, 2005  11:10
                                                                           b          n
                                  ξ 2            n
                                      b
                                                                           c
                                          c
                                                                               a          ξ 1
                                   P       e                ξ 1                e    E
                                                 E                        P
                                               a
                                      (a)                                       (b)
                            Figure 6.10. Typical cell face ab.

                            the bounding surface (line). The direction of C is anticlockwise. To make further
                            progress, the line integral is replaced by summation. Thus,

                                                     	          NK


                                                                    q

                                                          q · A =  (  · A) k ,                 (6.52)
                                                      C         k=1
                            where NK = 3 for a triangular element and k stands for the kth face of the control
                            volume. Thus, the line integral is discretized into NK segments.
                               To evaluate the dot product   · A at each cell face k, consider Figure 6.10, where
                                                       q

                            evaluation at face ab (say) shared by neighbouring cells P and E is to be carried out.
                            Let line PE be along the ξ 1 direction and line ab be along the ξ 2 direction, where the
                            latter direction is chosen such that Jacobian J (see Equation 6.14) is positive. Let
                            lines PE and ab intersect at e. Now, depending on the shapes of cells P and E, e may
                            lie within ab [Figure 6.10(a)] or on an extension of ab [Figure 6.10(b)]. Further, let
                              n be the unit normal vector to ab pointing outwards with respect to cell P as shown
                            in the figure. Then, using Equation 6.25, we get
                                                           ∂x 2    ∂x 1     1     2
                                            A = A ab · n = i    − j    = i β + j β ,           (6.53)



                                                                                  1
                                                                            1
                                                            ∂ξ 2   ∂ξ 2
                            where
                                                1
                                                                  2
                                              β = x 2b − x 2a ,  β =−(x 1b − x 1a ),           (6.54)
                                                1                 1
                                                       %
                                                         
  1    2  
  2    2
                                           A ab = A ck =  β   + β     = area of face ab,       (6.55)
                                                           1      1
                            and c is the midpoint of ab. The coordinates of c are
                                                             1
                                                       x i,c =  (x i,a + x i,b ).              (6.56)
                                                             2
                            Substituting Equation 6.53 in Equation 6.52, we have
                                                                         2
                                                      
  1      2         
   i
                              q                                      =             = (q n A c ) k . (6.57)
                             (  · A) ck = ( q · n) ck A ck = β q 1 + β q 2  β q i
                                                        1       1   k        1   k
                                                                        i=1
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