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334 ———  MATLAB: An Introduction with Applications


                   The parameters  α and  β indicate how much the acceleration enters into the velocity and displacement
                   equations at the end of the interval  ∆t. Therefore,  α and  β are chosen to obtain the desired integration
                   accuracy and stability. When α =1/6 and β =1/2, Eqs. (6.69) and (6.70) correspond to the linear acceleration
                   method (which can also be obtained using θ =1 in Wilson method). When α =1/2 and β = 0, the acceleration

                   is constant and equal to  X  during each time interval ∆t. If α = 1/2 and β = 1/8, the acceleration is constant
                                        t

                   from the beginning as  X  and then changes to X    t+∆ t  in the middle of the time interval ∆t. When α = 1/2 and
                                       t
                   β = 1/4, this corresponds to the assumption that the acceleration remains constant at an average value of

                   (X +  X    t+ ∆t )/2 . The finite difference formulas for the Newmark Beta scheme are
                     t



                                                     −
                                 { X t+ ∆  } =  1  { ( X t+ ∆t  t } { }) −  1  { } −    1  − 1   { }  ...(6.71)
                                                                  X
                                                                               X
                                                        X
                                                         t
                                                                                t
                                                                   t
                                          β∆t 2               β∆t        2β  
                                                                             α
                                                              α



                                                                        −
                                                     −
                                                       X
                                                                                   X
                                                                    X
                                 { X    t+ ∆  } =  β α  { ( X t+ ∆t  t } { }) −   β  − 1    { } ∆t    2β  − 1    { }  ...(6.72)
                                                         t
                                                                                     t
                                                                      t
                                           ∆t
                   Equation (6.13) can be employed to obtain a solution for displacements, velocity and accelerations at time
                                                                          {
                   t + ∆t. Therefore, by substituting the expressions for { X    t+ ∆  }  and  X   t+ ∆t  t }  from Eqs. (6.71) and (6.72),
                   respectively, into Eq. (6.13), we get
                               M   {X t+ ∆   } { t+ ∆t  t }                                      ...(6.73)
                             
                                        =
                                          F
                                              
                                                                             F
                                                 
                                              
                   where the effective mass matrix  M   and the effective force vector { t+ ∆t }  are given by
                                     M  =  1  M   α  [] [ ]
                                                       C +
                                                            K
                                          β ∆t 2 [ ] + β ∆t                                       ...(6.74)
                                                   1             α      

                                                                                X
                                 { F  t+ ∆t =  F  ∆t } +    − 1   M +    − 1   [] { }
                                                                           C
                                                          [ ] ∆t
                                                                             
                                                        
                                       } { t+
                                                                                 t
                                                   2
                                                  β             2β      
                                              1       α      
                                                             [] { }
                                                 M +
                                                   +    [ ]     − 1   C     X    t
                                                           
                                             β ∆t    β       
                                              1       α    
                                            +   2 [ ] +  [] { }                                    ...(6.75)
                                                                X
                                                  M
                                                          C
                                                            
                                                                 t
                                             β∆t     β ∆t  
                   Solution of Eq. (6.73) gives {X t+ ∆t  } , which is then substituted into Eqs. (6.71) and (6.72) in order to obtain
                   the accelerations and velocities at time t + t∆ . One of the features of Newmark Beta method is that for linear
                   systems the amplitude is conserved and the response is unconditionally stable, provided that
                       1        1    1 2                1         1
                   α≥    and β ≥   α+  . For values of  α=   and  β=  , the largest truncation errors occur in the
                       2        4    2                  2         4
                                                                                                       1
                   frequency of the response as opposed to other β values. It is also important to note that unless  β=  ,
                                                                                                       2
                                                                     1
                   there is a spurious damping introduced, proportional to  β−  . If β = 0, a negative damping results; this
                                                                     2
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