Page 349 - MATLAB an introduction with applications
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334 ——— MATLAB: An Introduction with Applications
The parameters α and β indicate how much the acceleration enters into the velocity and displacement
equations at the end of the interval ∆t. Therefore, α and β are chosen to obtain the desired integration
accuracy and stability. When α =1/6 and β =1/2, Eqs. (6.69) and (6.70) correspond to the linear acceleration
method (which can also be obtained using θ =1 in Wilson method). When α =1/2 and β = 0, the acceleration
is constant and equal to X during each time interval ∆t. If α = 1/2 and β = 1/8, the acceleration is constant
t
from the beginning as X and then changes to X t+∆ t in the middle of the time interval ∆t. When α = 1/2 and
t
β = 1/4, this corresponds to the assumption that the acceleration remains constant at an average value of
(X + X t+ ∆t )/2 . The finite difference formulas for the Newmark Beta scheme are
t
−
{ X t+ ∆ } = 1 { ( X t+ ∆t t } { }) − 1 { } − 1 − 1 { } ...(6.71)
X
X
X
t
t
t
β∆t 2 β∆t 2β
α
α
−
−
X
X
X
{ X t+ ∆ } = β α { ( X t+ ∆t t } { }) − β − 1 { } ∆t 2β − 1 { } ...(6.72)
t
t
t
∆t
Equation (6.13) can be employed to obtain a solution for displacements, velocity and accelerations at time
{
t + ∆t. Therefore, by substituting the expressions for { X t+ ∆ } and X t+ ∆t t } from Eqs. (6.71) and (6.72),
respectively, into Eq. (6.13), we get
M {X t+ ∆ } { t+ ∆t t } ...(6.73)
=
F
F
where the effective mass matrix M and the effective force vector { t+ ∆t } are given by
M = 1 M α [] [ ]
C +
K
β ∆t 2 [ ] + β ∆t ...(6.74)
1 α
X
{ F t+ ∆t = F ∆t } + − 1 M + − 1 [] { }
C
[ ] ∆t
} { t+
t
2
β 2β
1 α
[] { }
M +
+ [ ] − 1 C X t
β ∆t β
1 α
+ 2 [ ] + [] { } ...(6.75)
X
M
C
t
β∆t β ∆t
Solution of Eq. (6.73) gives {X t+ ∆t } , which is then substituted into Eqs. (6.71) and (6.72) in order to obtain
the accelerations and velocities at time t + t∆ . One of the features of Newmark Beta method is that for linear
systems the amplitude is conserved and the response is unconditionally stable, provided that
1 1 1 2 1 1
α≥ and β ≥ α+ . For values of α= and β= , the largest truncation errors occur in the
2 4 2 2 4
1
frequency of the response as opposed to other β values. It is also important to note that unless β= ,
2
1
there is a spurious damping introduced, proportional to β− . If β = 0, a negative damping results; this
2