Page 125 - Marks Calculation for Machine Design
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P1: Sanjay
                                      16:18
                          January 4, 2005
        Brown.cls
                 Brown˙C02
                              U.S. Customary     BEAMS            SI/Metric       107
                    Example 3. Calculate and locate the max-  Example 3. Calculate and locate the max-
                    imum shear force (V max ) and the maximum  imum shear force (V max ) and the maximum
                    bending moment (M max ) for the beam of  bending moment (M max ) for the beam of
                    Examples 1 and 2, where            Examples 1 and 2, where
                      F = 150 lb                        F = 700 N
                      L = 8ft                           L = 2.5 m
                      a = 3 ft, b = 5ft                  a = 1m, b = 1.5 m
                    solution                           solution
                    Step 1. Calculate the maximum shear force  Step 1. Calculate the maximum shear force
                    (V max ) from Eq. (2.63) as        (V max ) from Eq. (2.63) as
                             V max = F = 150 lb                V max = F = 700 N
                    Step 2. As shown in Fig. 2.94 this maximum  Step 2. As shown in Fig. 2.94, this maximum
                    shear force (V max ) of 150 lb occurs in the region  shear force (V max ) of 150 lb occurs in the region
                    to the right of the force (F).     to the right of the force (F).
                    Step 3. Calculate the maximum bending  Step 3. Calculate the maximum bending
                    moment (M max ) from Eq. (2.65) as  moment (M max ) from Eq. (2.65) as
                          M max = Fb = (150 lb)(5ft)        M max = Fb = (700 N)(1.5m)
                              = 750 ft · lb                     = 1,050 N · m
                    Step 4. As shown in Fig. 2.95 this maximum  Step 4. As shown in Fig. 2.95, this maximum
                    bending moment (M max ) of 750 ft · lb is located  bending moment (M max ) of 1,050 N · mis
                    at the right end of the beam, that is at the wall  located at the right end of the beam, meaning
                    support.                           at the wall support.
                                               F
                                      a                    b
                             A                                            B
                                           ∆

                                                   L
                             FIGURE 2.96  Beam deflection diagram.
                    Deflection. For this loading configuration, the deflection ( ) along the beam is shown in
                    Fig. 2.96, and given by Eq. (2.66a) for the values of the distance (x) from the left end of
                    the beam to the location of the force (F), at distance (a), and by Eq. (2.66b) for the values
                    of distance (x) from the force (F) to the right end of the beam.
                                       Fb 2
                                     =    (3L − 3 x − b)  0 ≤ x ≤ a            (2.66a)
                                       6 EI
                                       F (L − x) 2
                                     =          (3 b − L + x)  a ≤ x ≤ L       (2.66b)
                                          6 EI
                    where   = deflection of beam
                         F = applied force at intermediate point
                         x = distance from left end of beam
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