Page 127 - Marks Calculation for Machine Design
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P1: Sanjay
                                      16:18
                          January 4, 2005
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                 Brown˙C02
                              U.S. Customary     BEAMS            SI/Metric       109
                    Example 5. Calculate the maximum deflec-  Example 5. Calculate the maximum deflec-
                    tion (  max ) and its location for the beam con-  tion (  max ) and its location for the beam con-
                    figuration in Example 4, where      figuration in Example 4, where
                      F = 150 lb                         F = 700 N
                      L = 8ft                            L = 2.5 m
                      a = 3 ft, b = 5ft                  a = 1m, b = 1.5 m
                                                                  5
                                6
                     EI = 1.61 × 10 lb · ft 2           EI = 6.64 × 10 N · m 2
                    solution                           solution
                    Step 1. Calculate the maximum deflection at  Step 1. Calculate the maximum deflection at
                    the free end from Eq. (2.67).      the free end from Eq. (2.67).
                               Fb 2                               Fb 2
                          max =    (3L − b)                  max =    (3L − b)
                              6 (EI)                             6 (EI)
                                 (150 lb)(5ft) 2                   (700 N)(1.5m) 2
                            =              2                   =         5    2
                                      6
                              6 (1.61 × 10 lb · ft )             6 (6.64 × 10 N · m )
                              ×[3 (8ft) − 5ft)]                  ×[3 (2.5m) − 1.5m)]
                                                                         3
                                     3
                              3.75 × 10 lb · ft 2                1.575 × 10 N · m 2
                            =                                  =        6    2
                                     6
                              9.66 × 10 lb · ft 2                 3.98 × 10 N · m
                              ×[(24 − 5) ft]                     ×[(7.5 − 1.5) m]
                            = (3.88 × 10 −4 ) × (19 ft)        = (3.96 × 10 −4 ) × (6m)
                                       12 in                              100 cm
                            = 0.00737 ft ×                     = 0.00237 m ×
                                        ft                                  m
                            = 0.088 in ↓                       = 0.237 cm ↓
                    Example 6. Calculate the deflection (  a )  Example 6. Calculate the deflection (  a )
                    where the force (F) acts, where    where the force (F) acts, where
                      F = 150 lb                         F = 700 N
                      L = 8ft                            L = 2.5 m
                      a = 3 ft, b = 5ft                  a = 1m, b = 1.5 m
                                6
                                                                  5
                     EI = 1.61 × 10 lb · ft 2           EI = 6.64 × 10 N · m 2
                    solution                           solution
                    Step 1. Calculate the deflection (  a ) where  Step 1. Calculate the deflection (  a ) where
                    the force (F) acts from Eq. (2.68).  the force (F) acts from Eq. (2.68).
                               Fb 3                              Fb 3
                            a =                               a =
                              3 (EI)                             3 (EI)
                                (150 lb)(5ft) 3                   (700 N)(1.5m) 3
                            =                                  =
                                                                             2
                                           2
                                                                         5
                                      6
                              3 (1.61 × 10 lb · ft )             3 (6.64 × 10 N · m )
                                                                        3
                                     4
                              1.875 × 10 lb · ft 3               2.363 × 10 N · m 3
                            =                                  =        6   2
                                     6
                               4.83 × 10 lb · ft 2               1.99 × 10 N · m
                                      12 in                               100 cm
                            = 0.0039 ft ×                      = 0.00119 m ×  m
                                       ft
                            = 0.047 in ↓                       = 0.119 cm ↓
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