Page 180 - Materials Science and Engineering An Introduction
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152   •  Chapter 5  /  Diffusion

                       EXAMPLE PROBLEM 5.4

                         Diffusion Coefficient Determination
                         Using the data in Table 5.2, compute the diffusion coefficient for magnesium in aluminum at
                         550 C.

                         Solution
                         This diffusion coefficient may be determined by applying Equation 5.8; the values of D 0  and Q d
                                                4
                                                   2
                         from Table 5.2 are 1.2   10  m /s and 130 kJ/mol, respectively. Thus,
                                                                     (130,000 J/mol)
                                                   -4  2
                                         D = (1.2 * 10  m /s) expc -    #              d
                                                               (8.31 J/mol K)(550 + 273 K)
                                                       2
                                          = 6.7 * 10 -13  m /s

                       EXAMPLE PROBLEM 5.5

                         Diffusion Coefficient Activation Energy and Preexponential Calculations
                         Figure 5.8 shows a plot of the logarithm (to the base 10) of the diffusion coefficient versus re-
                         ciprocal of absolute temperature for the diffusion of copper in gold. Determine values for the
                         activation energy and the preexponential.
                         Solution
                         From Equation 5.9b the slope of the line segment in Figure 5.8 is equal to  Q d /2.3R, and the
                         intercept at 1/T   0 gives the value of log D 0 . Thus, the activation energy may be determined as
                                                                         (log D)
                                                Q d = -2.3R(slope) = -2.3R
                                                                       £    1   §
                  : VMSE                                                  a b
           D 0  and Q d  from                                               T
         Experimental Data                                log D 1 - log D 2
                                                  = -2.3R
                                                         £    1    1    §
                                                                -
                                                             T 1  T 2
                         where D 1  and D 2  are the diffusion coeffi-
                         cient values at 1/T 1  and 1/T 2 , respectively.   10 –12
                         Let us arbitrarily take 1/T 1    0.8   10  3
                                                    1
                            1
                         (K)  and 1/T 2    1.1   10  3  (K) . We   –13
                         may now read the corresponding log D 1    10
                         and log D 2  values from the line segment
                         in Figure 5.8.                       10 –14
                            [Before this is done, however, a  Diffusion coefficient (m 2 /s)
                         note of caution is offered: The vertical   10 –15
                         axis in Figure 5.8 is scaled logarithmi-
                         cally (to the base 10); however, the
                         actual diffusion coefficient values are  10 –16
                         noted on this axis. For example, for
                         D     10  14  m /s, the logarithm of D   10 –17
                                    2
                         is   14.0,  not  10  14 . Furthermore, this  0.7  0.8  0.9   1.0    1.1    1.2
                         logarithmic scaling affects the readings        Reciprocal temperature (1000/K)
                         between decade values; for example, at   Figure 5.8  Plot of the logarithm of the diffusion
                         a location midway between 10  14  and    coefficient versus the reciprocal of absolute
                         10  15 , the value is not 5    10  15  but,    temperature for the diffusion of copper in gold.
                         rather, 10  14.5    3.2   10  15 .]
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