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6.5  Elastic Properties of Materials   •   179

                        EXAMPLE PROBLEM 6.2

                          Computation of Load to Produce Specified Diameter Change
                          A tensile stress is to be applied
                          along the long axis of a cylindri-                     F
                          cal brass rod that has a diameter
                          of 10 mm (0.4 in.). Determine
                          the magnitude of the load re-      d 0                 d i           z
                                                  -3
                          quired to produce a 2.5 * 10 -
                                -4
                          mm (10 -in.) change in diame-
                          ter if the deformation is entirely                                           x
                          elastic.                                                            l  – l
                                                       l 0                 l i          z =  l  =  i  l  0
                                                                                           0   0
                          Solution
                                                                                              d  – d 0
                                                                                               i
                          This deformation situation is                                 x =  d 0  =  d 0
                          represented in the accompany-
                          ing drawing.
                             When the force F is applied,
                          the specimen will elongate in the
                          z direction and at the same time                       F
                          experience a reduction in diam-
                                          -3
                          eter, ≤d, of 2.5 * 10  mm in the
                          x direction. For the strain in the x direction,

                                                                 -3
                                                    d   -2.5 * 10  mm
                                              P x =   =                = -2.5 * 10 -4
                                                   d 0      10 mm
                          which is negative because the diameter is reduced.
                             It next becomes necessary to calculate the strain in the z direction using Equation 6.8. The
                          value for Poisson’s ratio for brass is 0.34 (Table 6.1), and thus

                                                                    -4
                                                          (-2.5 * 10 )
                                                    P x                           -4
                                              P z = -  = -             = 7.35 * 10
                                                     v         0.34
                          The applied stress may now be computed using Equation 6.5 and the modulus of elasticity,
                                                         6
                          given in Table 6.1 as 97 GPa (14 * 10  psi), as
                                                             -4
                                                                       3
                                          s = P z E = (7.35 * 10 )(97 * 10  MPa) = 71.3 MPa
                          Finally, from Equation 6.1, the applied force may be determined as

                                                        2
                                                    d 0
                                        F = sA 0 = s a  b p
                                                     2
                                                                  -3
                                                            10 * 10  m  2
                                                    6    2
                                          = (71.3 * 10  N/m ) a       b p = 5600 N (1293 lb f )
                                                                2
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