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6.7  True Stress and Strain  •  187

                                    For the static (low strain rate) situation, a measure of toughness in metals
                                 (derived from plastic deformation) may be ascertained from the results of a tensile
                  Tutorial Video:  stress–strain test. It is the area under the s–P curve up to the point of fracture. The
                     Mechanical   units are the same as for resilience (i.e., energy per unit volume of material). For a
                       Property   metal to be tough, it must display both strength and ductility. This is demonstrated
                    Calculations   in Figure 6.13, in which the stress–strain curves are plotted for both metal types.
                from Tensile Test   Hence, even though the brittle metal has higher yield and tensile strengths, it has a
                  Measurements   lower toughness than the ductile one, as can be seen by comparing the areas ABC
                                 and AB¿C¿ in Figure 6.13.




                          Concept Check 6.2  Of those metals listed in Table 6.3,
                          (a)  Which will experience the greatest percentage reduction in area? Why?
                          (b)  Which is the strongest? Why?
                          (c)  Which is the stiffest? Why?
                          [The answer may be found at www.wiley.com/college/callister (Student Companion Site).]





              Table 6.3  Tensile Stress–Strain Data for Several Hypothetical Metals to Be Used with Concept Checks 6.2 and 6.4

                              Yield            Tensile         Strain        Fracture           Elastic
              Material    Strength (MPa)   Strength (MPa)    at Fracture   Strength (MPa)   Modulus (GPa)
                 A             310              340             0.23           265               210
                 B             100              120             0.40           105               150
                 C             415              550             0.15           500               310
                 D             700              850             0.14           720               210
                 E                     Fractures before yielding               650               350




              6.7  TRUE STRESS AND STRAIN
                                 From Figure 6.11, the decline in the stress necessary to continue deformation past the
                                 maximum—point M—seems to indicate that the metal is becoming weaker. This is
                                 not at all the case; as a matter of fact, it is increasing in strength. However, the cross-
                                 sectional area is decreasing rapidly within the neck region, where deformation is oc-
                                 curring. This results in a reduction in the load-bearing capacity of the specimen. The
                                 stress, as computed from Equation 6.1, is on the basis of the original cross-sectional
                                 area before any deformation and does not take into account this reduction in area at
                                 the neck.
              true stress           Sometimes it is more meaningful to use a true stress–true strain scheme. True stress
                                    is defined as the load F                                         over
                                 s T                     divided by the instantaneous cross-sectional area A i
                                 which deformation is occurring (i.e., the neck, past the tensile point), or

              Definition of true                               s T =  F                             (6.15)
              stress                                                A i
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