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5.8 Discrete Fourier Transform                                                     365

                                    The real part of y tells us there is a cosine component with amplitude =3 and
                                    frequency =1, while the imaginary part of y says there is a sine component
                                    with amplitude =5 and frequency =1. This is depicted in the frequency
                                    domain shown in Figure 5.8.8.
                                            6
                                            5
                                            4
                                          Real Axis  3 2


                                            1
                                            0
                                                           1             2            3           4
                                                                      Frequency
                                            6
                                            5
                                            4
                                            3
                                            2 1
                                          Imaginary Axis  -1 0  1        2            3           4



                                           -2                         Frequency
                                           -3
                                           -4
                                           -5
                                           -6
                                                                  Figure 5.8.8
                                    Putting this information together allows us to conclude that the equation of the
                                    waveform must be x(τ)=3 cos 2πτ +5 sin 2πτ. Since
                                                                         n   4
                                                          1= max{f k } <   =   =2,
                                                                         2   2
                                    the information in just the first half of y

                                                               0        0
                                                      y n/2 =     +i       =3e 1 − 5ie 1
                                                               3       −5
                                    suffices to completely characterize x(τ).
                                        These elementary ideas help explain why applying F to a sample from a
                                    signal can reveal the oscillatory components of the signal. But there is still a
                                    significant amount of theory that is well beyond the scope of this example. The
                                    purpose here is to just hint at how useful the discrete Fourier transform is and
                                    why it is so important in analyzing the nature of complicated waveforms.
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