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5.8 Discrete Fourier Transform                                                     363

                                    The vector α cos 2πft is said to be in the time domain, while the pulses
                                    αe f and αe n−f are said to be in the frequency domain. The situation for
                                    β sin 2πft is similarly depicted in Figure 5.8.6 in which −βie f and βie n−f are
                                    considered two pulses of height −β and β, respectively.
                                              β



                                                                                          1
                                              0




                                              -β
                                                                    Time
                                                                   β sin πt


                                               βi                 n = 32      f = 4
                                                      4
                                               0
                                                            8        16        24   28   32
                                              - βi                 Frequency
                                                                     β
                                                                (1/16)F( sin πt  )
                                                                   Figure 5.8.6
                                    Therefore, if a waveform is given by a finite sum


                                                     x(τ)=     (α k cos 2πf k τ + β k sin 2πf k τ)
                                                            k
                                    in which the f k ’s are integers, and if x is the vector containing the values of
                                    x(τ)at n equally spaced points between time τ =0 and τ =1, then, provided
                                    that n is sufficiently large,

                                           2       2
                                            F n x =  F n    α k cos 2πf k t + β k sin 2πf k t
                                           n       n
                                                          k
                                                      2                      2

                                                 =      F n (α k cos 2πf k t)+  F n (β k sin 2πf k t)  (5.8.7)
                                                      n                     n
                                                    k                     k

                                                 =    α k (e f k  + e n−f k )+i  β k (−e f k  + e n−f k ) ,
                                                    k                    k
                                    and this exposes the frequency and amplitude of each of the components. If n is
                                    chosen so that max{f k } <n/2, then the pulses represented by e f and e n−f are
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