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                                   Microhinges and Microcantilevers: Lumped-Parameter Modeling and Design

                               Microhinges and Microcantilevers: Lumped-Parameter Modeling and Design  155
                                                         n
                                                         ™ z E A i
                                                               i
                                                            i
                                                         i =1
                                                   z N  =  n                            (3.149)
                                                          ™ E A i
                                                              i
                                                         i =1
                              The stiffness of this equivalent cantilever beam is
                                                          3(EI )
                                                              y e
                                                    k b,e  =                            (3.150)
                                                            l 3
                              It can also be shown that the mass fraction that has to be placed at the
                              free end of the microcantilever and that is dynamically equivalent to
                              the distributed mass of the multimorph is
                                                        n
                                                    33l ™ (ȡ A )
                                                              i
                                                           i
                                                       i =1        33                   (3.151)
                                             m    =             =     m
                                               b,e      140       140
                              where m is the mass of the whole multimorph. The first bending reso-
                              nant frequency is calculated by means of Eqs. (3.150) and (3.151) as

                                                     k b,e        (EI )
                                                                     y e
                                             Ȧ b,e  =    =3.567                         (3.152)
                                                     m
                                                      b,e          ml 3
                              In the case of a bimorph, Eq. (3.152) reduces to
                                                      2 4
                                                                      2
                                                                                 2
                                               2 4
                                        1.03 E t + E t +2E E t t (2t +3t t +2t )
                                                             1 2 1 2
                                               1 1
                                                                           1 2
                                                                      1
                                                     2 2
                                                                                 2
                                  Ȧ   =                                                 (3.153)
                                    b,e                                   2
                                                                    2 2 /
                                                  (E t + E t )(ȡ t + ȡ t ) l
                                                    1 1   2 2  1 1
                              When we  express  t 2  in terms of  t 1   according  to Eq. (3.132), then
                              Eq. (3.153) simplifies to
                                                                             4
                                                    2
                                           1.03t 1  E +2c 2+ c(3+2c) E E + c E 2 2
                                                                       1 2
                                                    1
                                    Ȧ    =                                              (3.154)
                                      b,e    2           (E + cE )(ȡ + cȡ )
                                             l             1    2  1    2
                              When c ĺ 0 (the bimorph becomes a unimorph formed of only material
                              1), Eq. (3.154) simplifies to
                                                              E I
                                                               1 y1
                                                  Ȧ = 3.567                             (3.155)
                                                    b            3
                                                              m l
                                                                1
                              which is the known relationship.
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