Page 33 - Mechanical design of microresonators _ modeling and applications
P. 33

0-07-145538-8_CH01_32_08/30/05



                                            Design at Resonance of Mechanical Microsystems

                              32   Chapter One
                                and the potential elastic energy is

                                                 1    2  1            1   2
                                                                   2
                                             U =   k x +  k (x ෹ x ) +  k x              (1.109)
                                                 2  1 1  2  2  2  1   2  3 2
                                By applying the Lagrange  equations approach, the  following differential
                                equations describing the free response of the system are obtained:
                                       ..                       ..
                                    m x1 + (k + k )x í k x =0 m x2 + (k + k )x í k x =0  (1.110)
                                      1     1  2  1   2 2      2     2  3  2   2 1
                                Equations (1.110) can also be written in vector-matrix form as
                                          0 { }       +   ෹k 2  k + k { x }  = { 0}      (1.111)
                                         m 1  0   .. x1  k + k 2  ෹k 2  x 1   0
                                                          1
                                                  ..
                                             m
                                               2
                                                                         2
                                                                    3
                                                                2
                                                  x2
                                The first matrix 0 in the left-hand side of Eq. (1.111) is the mass matrix,
                                whereas the second matrix is the stiffness matrix. The dynamic matrix is
                                                              k + k    k
                                                              1   2  í  2
                                                               m       m
                                                     í1         1       1
                                              A = M     K =                              (1.112)
                                                                k 2  k + k 3
                                                                     2
                                                              ෹
                                                               m      m
                                                                 2     2
                                The eigenvalues of this matrix are solutions to the characteristic equation,
                                and by taking the particular values of this problem, the corresponding reso-
                                nant frequencies are
                                                   3 í 3 k         3+ 3 k
                                             Ȧ =              Ȧ =                        (1.113)
                                              1      2   m     2     2   m
                                The first mode is expressed by the following equation:

                                            k + k           k
                                             1  2  ෹ Ȧ 2  ෹  2       (1)
                                              m      1     m       X
                                                                     (1) { 0}
                                                                     1
                                                             1
                                               1           3 { X }          0
                                                k 2    k + k             =               (1.114)
                                                        2
                                               ෹             ෹ Ȧ 2   2
                                                m        m      1
                                                 2        2
                                The first eigenvector is
                                                       1 {  ෹1+ 3
                                                     {X } =   1 }                        (1.115)
                                whereas the second eigenvector, which corresponds to the second resonant
                                frequency of Eq. (1.113), is




                           Downloaded from Digital Engineering Library @ McGraw-Hill (www.digitalengineeringlibrary.com)
                                      Copyright © 2004 The McGraw-Hill Companies. All rights reserved.
                                        Any use is subject to the Terms of Use as given at the website.
   28   29   30   31   32   33   34   35   36   37   38