Page 188 - Mechanics Analysis Composite Materials

Chapter 4. Mechanics of a composite layer 173

x,mm
-a 4 0 4 a
Fig. 4.40. Distribution of normalized stresses in longitudinal (a,,)and transverse (u,~)plies between the
cracks.

x, nam

-0.3 1

and
Fig. 4.41. Distribution of normalized shear (~,~~l)transverse normal stresses (a,?)at the ply interface
(z = hl) between the cracks.
0
OF = r&,(X = 0) = a,(l -k) ,
where k = kl/(k?c).For the foregoing example, k = 3.85 x So 0.~2m*x is so close
to 0: that we can assume that under practically the same load another crack occurs