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1,2-Elimination Reactions  367

      Table 7.12 ORIENTATION OF  THE  DOUBLE BOND IN  THE  PRODUCTS OF REACTION 7.37
                       2-Hexenel
      X                1-Hexene





                              --
      SOURCE: R. A. Bartsch and J. F. Bunnett, J. Amer. Chem. Soc., 90,408 (1968). Reprinted by permission
      of  the American  Chemical  Society.

     Table 7.13 PRODUCTS OF  REACTION 7.38  WITH  VARIOUS BASES
                                     Percent                  Percent
      Base          Solvent      (CHS)~C==CHCH~          (CH3),CHCH=CH2
      N(Bu) ,Br   Acetone             99.7
      N(Bu) ,CI   Acetone              99.2
      NaOEt       Ethanol             82
      KOtBu       t-Butanol           ,23.1

      SOURCE: G. Biale, D.  Cook, D. J. Lloyd, A. J. Parker, I. D. R. Stevens, J. Takahashi, and S. Win-
      stein, J. Amer.  Chem.  Soc.,  93,  4735  (1971). Reprinted  by  permission  of  the  American  Chemical
      Society.


      hydrogens  is  of  overriding  importance  to  product  determination.  Since  the
      acidity of the proton, the reactivity of the leaving group, and the strength of the
      base all help determine where the transition state lies in the spectrum, all of these
      affect the ratio of Hofmann to Saytzeff product.
          The strong electron-withdrawing ability  of fluorine,  which  renders  the
      protons acidic,  the  low  reactivity of this  halogen  as  a  leaving  group,  and  the
      strength of the base toward hydrogen assures that Reaction  7.37, when X  = F,
      lies well toward the E2H end of the spectrum. The data in Table 7.12 show that,
      CH3(CH2)3CH-CH3  2 CH3(CH2)2CH=CHCH3 +
                        - OCH
               I                                  CH3(CH2),CH=CH2        (7.37)
              X
      as expected, the more acidic primary  protons are lost preferentially  to the less
      acidic  secondary  ones,  giving  predominantly  Hofmann-type  product.  In  the
      series  of  increasing  atomic  weight,  the  halogens  become  simultaneously  less
      electron-withdrawing and better as leaving  groups; therefore  as the fluorine  is
      substituted in turn by C1, Br, and I, Reaction  7.37  moves more toward  the E,C
      end of the spectrum and Saytzeff products become more important.94
          The importance of the base in determining the nature of the transition state
      and thereby the product can be seen from Table  7.13.  When  Reaction  7.38  is
      carried out with KO-tBu in t-butanol (E2H conditions), 76.9 percent  Hofmann
      olefin  is  obtained.  However,  when  the  same  reaction  is  carried  out  with
      +N(Bu)~ Br-  (E2C conditions), 97.3 percent  Saytzeff product is obtained. The


      84  R. A.  Bartsch and J. F. Bunnett, J. Amer. Chem. Soc., 90, 408 (1968).
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