Page 38 - Modelling in Transport Phenomena A Conceptual Approach
P. 38

2.1.  MOLECULAR TRANSPORT                                            19


              Experimental measurements made at steady-state indicate that the rate of  heat
           flow per unit area is proportional to the temperature gradient, i.e.,
                                    6     Transport -
                                                   TI - To
                                    -=  k
                                    A       v        Y                       (2.1-3)
                                   Energy   DroDertv Temperature
                                           .. I
                                    flux           gradient
           The proportionality  constant,  k, between  the energy flux and  the  temperature
           gradient  is called  thermal  conductivity.  In SI units,  Q is in  W( J/s), A  in  m2,
           dT/dx in  K/ m, and k in  W/( m. K).  The thermal conductivity of  a material is,
           in general, a function of  temperature.  However, in many engineering applications
           the variation is sufficiently small to be neglected.  Thermal conductivity values for
           various substances are given in Table D.2 in Appendix D.
              The microscopic form of a. (2.1-3) is known as Fourier's  law of  heat conduction
           and is given by
                                                                             (2.1-4)

           in which the subscript y indicates the direction of the energy flux. The negative sign
           in Eq.  (2.1-4) indicates that heat flows in the direction of  decreasing temperature.

           Example  2.2  One side  of  a  wpper slab  receives a  net heat  input  at  a  rate  of
           5000W  due  to radiation.  The other face  is held  at  a  temperature  of 35°C.  If
           steady-state  conditions prevail,  calculate the surface temperature of  the side receiv-
           ing radiant energy.  The surface  area of  each face is 0.05m2, and the slab thickness
           is  4cm.

           Solution



















           Physical properties
              For copper: k = 398 W/ m. K
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