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1400-CH07  9/8/99  4:04 PM  Page 217






                                                               Chapter 7 Obtaining and Preparing Samples for Analysis  217

                 where the subscript indicates the extraction number. The concentration of S in the
                 aqueous phase after the extraction is

                                                 (moles aq) 1
                                              ]
                                           [S aq =                               7.21
                                                    V aq
                 whereas the solute’s concentration in the organic phase is
                                                 (moles org) 1
                                              ]
                                          [S org =                               7.22
                                                    V org
                 where V aq and V org are the volumes of the aqueous and organic phases. Solving
                 equation 7.20 for (moles org) 1 and substituting into equation 7.22 leave us with

                                            (moles aq) - (moles aq) 1
                                                    0
                                        ]
                                     [S org =                                    7.23
                                                    V org
                 Substituting equations 7.21 and 7.23 into equation 7.19, we obtain
                                              ]/                V
                         [(moles aq) 0  -(moles aq) 1  V org  (moles aq) 0aq  -(moles aq) 1 V aq
                     D =                            =
                                (moles aq) 1  /  V aq        (moles aq) 1 V org
                 Rearranging and solving for the fraction of solute remaining in the aqueous phase
                 after one extraction, (q aq ) 1 , gives
                                           (moles aq) 1    V aq
                                    (q aq 1 =         =                          7.24
                                       )
                                           (moles aq) 0  DV org +  V aq

                 The fraction present in the organic phase after one extraction, (q org ) 1 , is
                                      (moles org) 1             DV org
                                  )
                              (q org 1 =          = 1 - (q aq 1  =
                                                         )
                                      (moles org) 0           DV org +  V aq

                 Example 7.14 shows how equation 7.24 is used to calculate the efficiency of a simple
                 liquid–liquid extraction.
                            7 4
                     EXAMPLE  .1
                     A solute, S, has a K D between water and chloroform of 5.00. A 50.00-mL
                     sample of a 0.050 M aqueous solution of the solute is extracted with 15.00 mL
                     of chloroform. (a) What is the extraction efficiency for this separation?
                     (b) What is the solute’s final concentration in each phase? (c) What volume of
                     chloroform is needed to extract 99.9% of the solute?
                     SOLUTION
                     For a simple liquid–liquid extraction, the distribution ratio, D, and the
                     partition coefficient, K D , are identical.
                     (a) The fraction of solute remaining in the aqueous phase after the extraction
                        is given by equation 7.24
                                                 50 .00  mL
                                  (q aq 1 =                       =  . 0 400
                                     )
                                         (5.00)(15.00 mL) + 50 .00  mL
                        The fraction of solute present in the organic phase is, therefore, 0.600.
                        Extraction efficiency is the percentage of solute successfully transferred
                        from its initial phase to the extracting phase. The extraction efficiency is,
                        therefore, 60.0%.
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