Page 235 - Modern Analytical Chemistry
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              218    Modern Analytical Chemistry


                                                  (b) The moles of solute present in the aqueous phase before the extraction is
                                                                               . 0 050  mol
                                                      (Moles aq) 0 = S  ] ´V aq =         . ´ 0 05000  L  . = 0 0025  mol
                                                                  [ aq 0
                                                                                  L
                                                     Since 40.0% of the solute remains in the aqueous phase, and 60.0% has
                                                     been extracted into the organic phase, the moles of solute in the two
                                                     phases after extraction are
                                                     (Moles aq) 1 = (moles aq) 0 ´(q aq ) 1 = 0.0025 mol ´(0.400) = 0.0010 mol

                                                  (Moles org) 1 = (moles aq) 0 – (moles aq) 1 = 0.0025 mol – 0.0010 mol = 0.0015 mol
                                                     The solute’s concentration in each phase is
                                                                      (moles aq) 1  . 0 0010  mol
                                                                 ]
                                                              [S aq 1 =         =            =  . 0 020  M
                                                                         V aq      . 0 05000  L
                                                                      (moles org) 1  . 0 0015  mol
                                                                  ]
                                                                                                .  M
                                                              [S org 1 =         =            = 01 0
                                                                         V org       . 0 01500  L
                                                  (c) To extract 99.9% of the solute (q aq ) 1 must be 0.001. Solving equation 7.24
                                                     for V org , and making appropriate substitutions for (q aq ) 1 and V aq gives
                                                            V aq -( q aq ) 1  V aq  50 .00  mL -( .001 )( .00  mL)
                                                                                      0
                                                                                           50
                                                      V org =            =                          = 9990  mL
                                                                                          0
                                                               ( q aq ) 1 D       (.001 )( . )
                                                                                           0
                                                                                   0
                                                                                        5
                                                     Clearly, a single extraction is not reasonable under these conditions.
                                                  In Example 7.14 a single extraction results in an extraction efficiency of only
                                              60%. If a second extraction is carried out, the fraction of solute remaining in the
                                              aqueous phase, (q aq ) 2 , is given by
                                                                        (moles aq) 2    V aq
                                                                    )
                                                                (q aq 2 =          =
                                                                        (moles aq) 1  DV org +  V aq
              Colorplate 4 shows an example of a  If the volumes of the aqueous and organic layers are the same for both extractions,
              liquid–liquid extraction.       then the cumulative fraction of solute remaining in the aqueous layer after two ex-
                                              tractions, (Q aq ) 2 , is
                                                                                                      2
                                                                 (moles aq) 2            æ    V aq   ö
                                                         (Q aq 2 =          = (q aq 1  )  ç          ÷
                                                             )
                                                                                 ) (q aq 2 =
                                                                 (moles aq) 0            è DV org + V aq ø

                                              In general, for a series of n identical extractions, the fraction of analyte remaining in
                                              the aqueous phase after the last extraction is
                                                                                         n
                                                                             æ    V aq  ö
                                                                         ) n =
                                                                     (Q aq   ç          ÷                     7.25
                                                                             è DV org + V aq ø
                                                         7 5
                                                  EXAMPLE  .1
                                                  For the extraction described in Example 7.14, determine (a) the extrac-
                                                  tion efficiency for two extractions and for three extractions; and
                                                  (b) the number of extractions required to ensure that 99.9% of the solute is
                                                  extracted.
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