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148                       Relationships among Reactants

                With the empirical function



             equation (7.20) becomes

                                                 2
                       /'JI = /'JIo + J (l1a + I1bT + I1CT ) dT = /'JIo  + l1aT + ~b T2 + ~C T3.
                Coefficients l1a, I1b/2, and I1cl3 calculated from the pertinent numbers in table 7.1 are


                        l1a = -2.215 J K· 1 , I1b  = -1.422 x 10-3 J K- 2  , I1c  = 8.533 x 10- 7  J K-3.
                                        2                    3
             Then term /'JIo  is

                                I1b
                                    2  I1c
                                           3
              /'JIo  =/'JIT  -l1a1i --1i --1i
                       1         2      3
                 = -92,312+2.215(298.15)+ 1.422 x 1O-3(298.15r -8.533 x 1O-7(298.15t J = -91,548 J.
             Inserting these parameters into the general form gives us
                          /'JI~ = -91,548 - 2.215T -1.422 x 1O-3T2 + 8.533 x 10- 7  T3 J.



             7.6 Calorimetric Entropy
                In determining the Gibbs free energy change I1G for a reaction, a person needs not
             only /'JI but also 68 for converting the reactants to products. The increment in entropy
             is obtained from the entropies of the pure participants. These may be found from energy
             capacity measurements made down to very low temperatures coupled with the third law
             of thermodynamics.
                The entropy change occasioned by raising the temperature of a given phase at con-
             stant pressure from Tl to T2 is
                                             68 =  rT2 C p  dT                       [7.21]
                                                 JTl  T   '
             following formula (5.22).  The entropy change occasioned by a first-order transition at
             temperature T2  is

                                                                                     [7.22]

             following formula (5.23).
                Below about 15 K,  energy capacity measurements become very difficult. But there a
             theoretical result of Paul Debye may be employed. By considering the possible elastic
             waves set up in a condensed phase, he determined that

                                                Cp  ~aT3                             [7.23]
             at the low temperatures. So we find that

                                     T  C       T           '7"'3  (C p )
                                68= r 1 ~ dT= r laT2 dT=a_-l1_= __ T_l.              [7.24]
                                    Jo  T      Jo           3      3
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