Page 219 - Modern physical chemistry
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212                             Electrochemistry

                For the anion in the anode compartment, we have

                                             dnelectrolysis = 0
             since anions are not oxidized at the electrode. But from the electrical neutrality condi-
             tion, the change in equivalents of the cation equals the change in equivalents of the anion.
             For either ion,
                                   dn = 0.9972 _ 0.7532 = 0.2440  e  uiv.
                                        31.773  31.773  31.773  q
                Combining these results as in equation (9.26) gives us

                                                   0.2440    .
                                        dnmigration = -- eqmv
                                                   31.773
             for the anion. Dividing the equivalents migrating by the equivalents reduced at the cathode,
             as in (9.21), leads to
                                       L  =  0.2440/31.773 = 0.6100.
                                           0.4000/31.773
             Because the transference numbers of the ions add up to 1, we have

                                            t+  = 1- L  = 0.3900.
                On the other hand, for the cation in the anode compartment, we have

                                                    0.4000   .
                                        dnelectrolysis = -- eqmv.
                                                    31.773
             As before, the change in equivalents in the compartment is

                                                0.2440    .
                                           dn=-- eqmv.
                                                31.773
             So for the equivalents of cation migrating into the anode compartment, equation (9.26)
             yields
                               dn.  .  - 0.2440 _ 0.4000 = _ 0.1560  e  uiv
                                  nugration  - 31.773  31.773   31.773  q   .

             To get the amount migrating out, one changes the sign. Dividing the result by the equiv-
             alents oxidized at the electrode then gives us

                                       t  = 0.1560/31.773 = 0.3900.
                                        +  0.4000 / 31.773
             whence
                                            L  = I-t+ = 0.6100.


             9.4 Moving Ion Clouds and Boundaries
                How a configuration of ions moves can be determined from the movement of a suit-
             able boundary. This provides a second method for measuring transference numbers.
                Through a  region where an electrolyte is uniform, an imposed electric intensity E
             causes the cations to drift in the same direction at the average velocity u+ and the anions
             to drift in the opposite direction at the average velocity u .. In unit time, the cations travel
             distance u+ on average, while the anions travel distance u. in the opposite direction on
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