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152     3 Matrix eigenvalue analysis



                   angles at their natural values of θ a = 2π/3. Let θ αβγ be
                                                         (
                                                r [αβ]  · r [γβ]  [αβ]  [β]  [α]
                              [α]  [β]  [γ ]                   r   = r   − r
                       θ αβγ r  ,r  ,r  = acos                  [γβ]   [β]  [γ ]     (3.275)
                                               r
                                                     r
                                                 [αβ]    [γβ]   r   = r  − r
                   We resist bending of this angle away from its natural value θ a = 2π/3 by adding to the
                   potential energy an angle-bending contribution
                              [a]     [α]  [β]  [γ ]     1        [α]  [β]  [γ ]       2
                            U    r  ,r  ,r   = K a θ αβγ r  ,r  ,r                   (3.276)
                              αβγ              2                    − θ a
                   For each angle in the energy model for this 2-D molecule, we use
                                             K a = 1   θ a = 2π/3                    (3.277)

                   For a real molecule, we would include additional terms from van der Waal’s and electro-
                   static nonbonded interactions, but here for simplicity we consider only the bonded energy
                   contributions. Let the coordinate vector be
                                       q = [x 1 y 1 x 2 y 2 x 3 y 3 x 4 y 4 x 5 y 5 x 6 y 6 ] T  (3.278)

                   The potential energy of the molecule is
                                          [b]   [b]   [b]  [b]   [b]
                                 U(q) = U   + U   + U   + U   + U
                                          12    13   14    25    26
                                            [a]   [a]   [a]   [a]   [a]   [a]
                                        + U   + U   + U   + U   + U   + U            (3.279)
                                            213   214   314   125   126   526
                   and the kinetic energy is

                             m 1 ˙r   m 1 ˙r   m 2 ˙r    m 2 ˙r   m 2 ˙r   m 2 ˙r
                                          [2]
                                                                      [5]
                                                                               [6]
                                                    [3]
                                                             [4]
                                 [1]
                    K(q, ˙q) =      +        +        +         +        +           (3.280)
                               2         2        2        2        2         2
                   where m 1 = 10 and m 2 = 1. We can then compute the mass matrix M such that
                                                        1 T
                                               K(q, ˙q) = ˙q M ˙q                    (3.281)
                                                        2
                   Your task is to write a MATLAB program that computes the vibrational frequencies, through
                   the following steps:
                   (a) Write a routine that sets the atomic positions, with r [1]  = 0, such that all bond lengths
                      and angles take their natural values. This is a minimum potential energy state. Store
                      the results as a state vector ˆ q.
                  (b) Write a routine that returns, for input q, the potential energy U(q).
                   (c) Using the routine from (b), write a routine to compute the elements of the Hessian
                      matrix
                                                               2
                                                              ∂ U
                                         [H(ˆq)] mn = [H(ˆq)] nm =                   (3.282)

                                                             ∂q m q n ˆq
                      This can be done numerically by finite differences,

                                   ∂    ∂U      (∂U/∂q n )| ˆq+εe [m] − (∂U/∂q n )| ˆq−εe [m]
                       [H(ˆq)] mn =            ≈                                     (3.283)
                                  ∂q m  ∂q n     ˆ q          2ε
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