Page 335 - Physical Principles of Sedimentary Basin Analysis
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10.1 Newton’s law of gravity                317

                     68
                                         −2200
                                          −2000                 −200
                                       −1800
                            −1400   −1600
                    latitude [deg]  67  −1200                  −400    [m]  0

                           −1000

                      −800                                                −500
                                                                          −1000
                                                                          −1500
                                                                          −2000
                      −600                                                −2500
                     66
                       6         7        8        9        10        11
                                          longitude [deg]
                                              (a)
                     68
                                                               70
                                                            50
                                                        40
                    latitude [deg]  67 −20   −10   −30   90   80       [mGal]


                                                                          100
                                                                          80
                                                                          60
                                  60                                      40
                                                30         10             20
                                                                          0
                                                                          −20
                                    20                    0               −40
                     66
                       6         7        8        9        10        11
                                         longitude [deg]
                                              (b)
            Figure 10.1. (a) Water depth over a part of the Lofoten ridge, Norway. (b) Free-air gravity over the
            area in (a) reveals the ridge as a gravity anomaly. The ridge is basement rock that pierces through
            sediments with a substantially lower density.

                                                                  3
                                                                       s
            where G is the universal gravitational constant G = 6.67 · 10 −11  m kg −1 −2 . The gravi-
            tational acceleration of an object, for example a piece of rock, with mass m falling towards
            the Earth follows from Newton’s second law of mechanics. It says that the acceleration is
            the force divided by the mass:
                                             F      M
                                         g =    = G                            (10.2)
                                             m      r 2

            where M is the mass of the Earth. Force and acceleration are vectors, because they are
            quantities with a direction. The gravity of a point mass M on the point mass m is directed
            from m to M. The gravitational force is written with direction using the unit vector
            n r = r/r, where r is the vector from M to m, and where r =|r|. Newton’s law is then

                                                 Mm
                                         F =− G      n r                       (10.3)
                                                 r 2
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