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260    ACIDS AND BASES

                                      The equilibrium constant for the dissociation of H 2 SO 4 :
              The subscript (1) tells
                                                                          +
                                                                      −
              us we are considering                              [HSO ][H ]
                                                                      4
              the first proton to be                       K a(1) =  [H 2 SO 4 ]
              lost.
                                      Similarly,
                                                                          +
                                                                     2−
                                                                  [SO ][H ]
                                                                     4
              K a(1) is always bigger                     K a(2) =  [HSO 4 ]
                                                                         −
              than K a(2) .
                                        In fact, we can also extend this treatment to bases, looking at
                                      the step-base addition of protons.
                      SAQ 6.10 The tetra-protic acid H 4 EDTA (V) has four possible proton
                      equilibrium constants. Write an expression for each, for K a(1) to K a(4) .




                       Why is an organic acid such as trichloroethanoic acid
                       so strong?

                      Effect of structure on the K a of a weak acid


                      The value of K a for trichloroacetic acid CCl 3 COOH (VIII) is very large at 0.23.
                                                              −
                      Indeed, it is stronger as an acid than the HSO ion – quite remarkable for an organic
                                                              4
                      acid!
                                                      Cl       O


                                                    Cl
                                                      Cl       OH
                                                         (VIII)


                        Let us return to the example of ethanoic acid (I). The principal structural difference
                      between I and VIII is the way we replace each of the three methyl protons in ethanoic
                      acid with chlorine atoms.
                        The three methyl protons in I are slightly electropositive, implying that the central
                      carbon of the –CH 3 group bears a slight negative charge. This excess charge is not
                      large, but it is sufficient to disrupt the position of the acid-dissociation equilibrium, as
                      follows. Although the undissociated acid has no formal charge, the ethanoate anion
                      has a full negative charge, which is located principally on the carboxyl end of the
                      anion. It might be easier to think of this negative charge residing on just one of the
                                      oxygen atoms within the anion, but in fact both oxygen atoms and
              Delocalization is a     the central carbon each bear some of the charge. We say the charge
              means of stabilizing    is delocalized, according to structure IX, which is a more accurate
              an ion.                 representation of the carboxylate anion than merely –COO .The
                                                                                          −
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