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                                                            Power electronic control in electrical systems 103



























                      Fig. 3.21 Series compensated line: phasor diagram.

                      Using these relationships, and taking V m as reference phasor, it is possible to derive
                      the basic power-transfer characteristic as
                                                                           d
                                                       E s V m
                                        P ˆ                              sin             (3:50)
                                                       X Cg     y  Z 0  y  2
                                            Z 0 sin y=2    cos ‡   sin
                                                        2     2  X    2
                      with
                                             d          y  Z 0   y         d
                                        E s cos  ˆ V m cos  ‡  sin  ˆ E r cos            (3:51)
                                             2          2   X    2         2
                      If V m is substituted from equation (3.51) into equation (3.50), the following result is
                      obtained for the symmetrical line, if E s ˆ E r :

                                                        E s E r
                                                                    i sin d              (3:52)
                                         P ˆ h
                                                       X Cg
                                              Z 0 sin y    (1 ‡ cos y†m m
                                                        2
                      where
                                                  Z 0  sin y      Z 0   y
                                           m ˆ 1 ‡           ˆ 1 ‡   tan                 (3:53)
                                                   X 1 ‡ cos y     X    2
                      With no shunt reactors, m ˆ 1. With fixed terminal voltages, E s ˆ E r ˆ E, the
                      transmission angle d can be determined from equation (3.52) for any level of power
                      transmission below the maximum. Once d is known, V m can be determined from
                      equation (3.50). Then V 1 , V 2 , V Cg and other quantities follow.
                        One simplification is to ignore the shunt capacitance of the line and remove the
                      shunt reactors. Then Z 0 sin y is replaced by X L and m ˆ 1, so that with E s ˆ E r ˆ E,
                                                         E 2
                                                  P ˆ         sin d                      (3:54)
                                                      X L   X Cg
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