Page 159 - Process Equipment and Plant Design Principles and Practices by Subhabrata Ray Gargi Das
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156    Chapter 5 Heat exchanger network analysis





               Table P5.4A Stream specification table.
                                                                  TS [            TT [


                                                                  TSLðDT min =2Þ  TTLðDT min =2Þ
                                                                  for hot stream  for hot stream
                                                                  TS [            TT [


                                               CP                 TSLðDT min =2Þ  TTDðDT min =2Þ
               Stream          TS      TT     (kW/                for cold stream  for cold stream
                no.    Type    ( C)   ( C)       C)    DH(kW)         ( C)            ( C)




               1       Hot    170     60     2.5        275      165             55
               2       Hot    150     30     1          240      145             25
               3       Cold   20      135    1.5       172.5     25              140
               4       Cold   80      140    4         280       85              145
              Hot and cold utilities are available at temperatures above the highest and the lowest temperatures in the process.


                Solution
                The temperature interval heat balance and the problem table cascade as shown in Table P5.4B is
             created using the information in Table P5.4A. The heat flow across 85 C is ‘0’and therefore for the

             process, the pinch temperature is 85 C. Since the pinch is based on DT min ¼ 10 C, the hot and the cold


             pinch temperatures are 90 C and 80 C, respectively.


               Table P5.4B Temperature interval heat balance and problem table cascade.
                     CP = 2.5                                          0 kW     62.5 kW
                                               ( ΣCP –ΣCP )  ΔH Interval
                                                   C
                                                        H
               165°C   1
                          CP = 1.0         20°     –2.5      –50             –50
               145°C         2                                            50         112.5
                                            5°     0.5       2.5             2.5
               140°C                                                      47.5       110
                                           55°  5.5–3.5 = 2.0  110           110
                85°C                   4                                  –62.5      0
                                    CP = 4.0 30° 1.5–3.5 = –2.0  –60         –60
                55°C                                                      –2.5       60
                                           30°  1.5–1.0 = 0.5  15            15
                25°C              3                                       –17.5      45
                               CP = 1.5
                                             HU = 62.5 kW ; CU = 45 kW
                                       T c, pinch  = 80°C, T pinch  = 85°C, T h, pinch  = 90°C
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